Find the maximum or minimum of the following quadratic function: y = 16x2+ 40x + 25.

Mathematics

1 answer:

Irina-Kira [14]3 years ago

4 0

the answer to your question is c. -25

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$\bf \textit{area of a sector of a circle}\\\\
A=\cfrac{\theta \pi r^2}{360}\quad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
A=8\\
r=4
\end{cases}\implies 8=\cfrac{\theta \pi 4^2}{360}\implies \cfrac{8\cdot 360}{4^2\pi }=\theta 
\\\\\\
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$\bf \textit{arc's length}\\\\
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\\\\\\
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if you do a quick calculation on what that angle is, you'll notice that it is exactly 1 radian, and an angle of 1 radian, has an arc that is the same length as its radius.

that's pretty much what one-radian stands for, an angle, whose arc is the same length as its radius.

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