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Naya [18.7K]
2 years ago
6

U/v * 5 where u = 4 and v = 6

Mathematics
1 answer:
Ann [662]2 years ago
7 0
4 divided by 6 times 5 equals 3.333
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Nine voltage measurements in a circuit have produced the following values: 12.09, 12.05, 11.94, 11.99, 12.12, 12.05, 12.02, 11.9
Debora [2.8K]

Answer:

we can not reject any value

Step-by-step explanation: From data we can test the highest and the lowest value to evaluate if one of these values are out of certain confidence Interval

If we established CI = 95 % then  α = 5 % and  α/2 = 0,025

From data we find the mean of the values

μ₀  = 12,03   and σ = 0,07

From z table we find z score for 0,025 is  z(c) = ± 1,96

So limits of our CI are:

12,03 + 1,96 =  13,99

12,03 - 1,96 = 10,07

And all our values are within  ( 10,07 , 13,99)

So we can not reject any value

4 0
3 years ago
Math question plz help
Svetach [21]

Answer:

Yes they are.

Because:

As said in the rules you have to keep the bases and add the exponents.

7 0
3 years ago
Read 2 more answers
Please help!!
ivanzaharov [21]
Take half of the coefficient on the x term
8 0
4 years ago
Read 2 more answers
Which choice is the explicit formula for the following geometric sequence? 0.2, -0.06, 0.018, -0.0054, 0.00162
Crazy boy [7]

Answer:

aₙ = 0.2(-0.3)⁽ⁿ⁻¹⁾

Step-by-step explanation:

The geometric sequence with the first term a, a common ratio r has the nth term given as

Tₙ = arⁿ⁻¹

where Tₙ is the nth term

From the given sequence

a = 0.2

r = -0.06/0.2

= -0.3

Hence the nth term

= 0.2 * -0.3ⁿ⁻¹

The right option is E

8 0
3 years ago
An open box is to be constructed so that the length of the base is 3 times larger than the width of the base. If the cost to con
natta225 [31]

Answer:

Step-by-step explanation:

Let assume that the volume = 88 cubic feet

Then:

L = 3w --- (1)volume = l \times w \times h \\ \\ 88 =  (3w)   \times w  \times h \\ \\ 3w^2 h= 88 \\ \\ h = \dfrac{88}{3w^2}--- (2) \\ \\

The construction cost now is:

C = 4(l \times w) + 2 ( w  \times h) + 2(l \times h) \\ \\ C = 4(3w^2) + 2(w  \times \dfrac{88}{3w^2}) + 2(3w \times \dfrac{88}{3w^2}) \\\\ C = 12w^2 + \dfrac{176}{3w} + \dfrac{176}{w}

Now, to determine the minimum cost:

\dfrac{dC}{dw}= 0  \\ \\ \implies 24 w - \dfrac{176}{3w^2}- \dfrac{176}{w^2}=0 \\ \\ 24 w ^3 = \dfrac{176}{w^2}(\dfrac{1}{3}+1) \\ \\ 24 w ^3 = \dfrac{176(4)}{3} \\ \\ w^3 = \dfrac{88}{3(3)}

w = \dfrac{88}{3(3)}^{1/3} \ feet

Now;

length = 3 ( \dfrac{88}{3(3)})^{1/3} \ feet

height = ( 88})^{1/3} (3)^{1/3} \ feet

6 0
3 years ago
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