Volume of a cone = (1/3) pi x r^2 x h
Volume of a cylinder = pi x r^2 x h
Volume of the cylinder = pi x 2^2 x 3 = 37.68 cubic inches
Now set the volume for the cone to the volume of the cylinder and solve for the height.
37.68 = (1/3) x pi x r^2 x h
37.68 = (1/3) x pi x 3^2 x h
37.68 = (1/3) x pi x 9 x h
37.68 = 9.42 x h
h = 37.68 / 9.42
h = 4
The height of the cone is 4 cm.
Add it up then you will get answer
To simulate the probability in a spinner divide the spinner into colors depending on the probability each color represents.
<h3>What does the word "probability" mean?</h3>
This word refers to the likelihood for an event to occur. Moreover, it is often expressed either as a fraction, a percentage, or a number.
<h3>How to create a spinner to simulate probability?</h3>
In this case, each of the colors represents a probability:
- Green 20%
- Blue 1/4 or 25%
- Yellow 2/5 oe 40%
- Orange 15%
Due to this, the best is to divide the spinner by colors and considering the percentanges of each color. For example 40% of the spinner should be red, while 15% should be orange.
Learn more about spinner in: brainly.com/question/24280611
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Answer:
The ray that goes parallel to the main axis after passing through the lens should also be parallel from the object to the lens
Step-by-step explanation:
To form the image of an object using a convex lens, ray diagrams are used. The following steps are followed when drawing ray diagrams.
1) Light rays are drawn from the object incidented on the lens and parallel to the principal axis. The incident light refracts (bends) through the lens and converges at the focal point at the other side of the lens.
2) Another incident light passes through the optical centre undeflected and intersect with the refracted ray at the other side of the lens.
Based on the above points, Roshan made an error by drawing the ray that goes parallel to the main axis and after passing through the lens made the same ray to be parallel from the object to the lens instead of refracting (bending) after passing through the lens.
