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11111nata11111 [884]
3 years ago
6

The plans for a rectangular deck call for the width to be 4 feet less than the length. Sam wants the deck to have an overall per

imeter of 52 feet. What should the length of the deck be?
Mathematics
1 answer:
Lelechka [254]3 years ago
3 0

Since rectangles have two pairs of equal-length sides, for any rectangle with length L and width W, its perimeter is always 2L + 2W (or 2(L + w), whichever you prefer). Here, we're told that the width is 4 feet less than the length. Symbolically, we'd say that W = L - 4. This allows us to write the perimeter entirely in terms of length if we replace our W with the expression on the right side:

2L + 2W = 2l + 2(L - 4) = 2L +2L - 8 = 4L - 8

Sam wants this expression to come out to 52, so we can set up the equality 4L - 8 = 52 and solve for L to find what the length has to be:

Adding 8 to either side, the equality becomes 4L = 60. Diving either side by 4 gives us L = 15, which tells us that the length of the deck should be 15 feet.

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Two forces with magnitudes of 100 and 50 pounds act on an object at angles of 50° and 160°, respectively. Find the direction and
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Forces in direction x:
 
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 Forces in direction y:
 
fy1 = 100 * sine (50) = 76.60
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theta = atan (fy / fx)
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 theta = 79.55 degrees
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The direction and magnitude of the resultant force are:
 
f = 95.28 pounds at theta = 79.55 degrees
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