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3 years ago

Suppose that f(x)=3x+1....

Mathematics

1 answer:

skad [1K]3 years ago

4 0

Answer:

Step-by-step explanation:

f(x) = 3x+1

f(x+h) = 3(x+h)+1 = 3x+3h+1

f(x+h) - f(x)= 3x+3h+1-3x-1 = 3h

3h/h=3

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Which of the following is equivalent to the expression 2x + 3x +4x (x-2)

Alex787 [66]

Answer:

Step-by-step explanation:

add and the take the parathesis out and there you have ur answer

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3 years ago

The graph of an absolute value function opens down and has a vertex of (-3,0).

dsp73

I wrote the domain and range in interval notation, not sure if that’s how you’re asked to do it. This is how I was taught to state the domain/range of a graph.

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3 years ago

Read 2 more answers

Graph the solution of y - 4 < 2 on a number line.

Luda [366]

Answer:

y<6

Step-by-step explanation:

You will solve it like a one-step equation but just leave the less then symbol. so anything less then 6 is your answer

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3 years ago

Find four numbers that form a geometric progression such that the third term is greater than the first by 12 and the fourth is g

olchik [2.2K]

If $x$ is the first number in the progression, and $r$ is the common ratio between consecutive terms, then the first four terms in the progression are

$\{x,xr,xr^2,xr^3\}$

We want to have

$\begin{cases}xr^2-x=12\\xr^3-xr=36\end{cases}$

In the second equation, we have

$xr^3-xr=xr(r^2-1)=36$

and in the first, we have

$xr^2-x=x(r^2-1)=12$

Substituting this into the second equation, we find

$xr(r^2-1)=12r=36\implies r=3$

So now we have

$\begin{cases}9x-x=12\\27x-3x=36\end{cases}\implies x=\dfrac32$

Then the four numbers are

$\left\{\dfrac32,\dfrac92,\dfrac{27}2,\dfrac{81}2\right\}$

4 0

3 years ago

Find the perimeter of pentagon STUVW WITH VERTICES S(0,0) T(3,-2) U(2,-5) V(-2,-5) W(-3,-2)

andrew11 [14]

Use the distance formula.

$\sqrt{( x_{2} - x_{1} )^2 + (y_{2} - y_{1})^2}$

Points S and W.
$\sqrt{(3)^2 + (2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points S and T
$\sqrt{(3 - 0)^2 + (-2 - 0)^2}$

$\sqrt{(3)^2 + (-2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points T and U
$\sqrt{(3 - 2)^2 + (-2 + 5)^2}$

$\sqrt{(1)^2 + (3)^2}$

$\sqrt{1+9}$

$\sqrt{10}$

~3.1

Points U and V
$\sqrt{(2+2)^2 + (-5 + 5)^2}$

$\sqrt{(4)^2 + (0)^2}$

$\sqrt{16}$

~4

Points V and W
$\sqrt{(-2+3)^2 + (-5 + 2)^2}$

$\sqrt{(1)^2 + (-3)^2}$

$\sqrt{2+9}$

$\sqrt{11}$

~3.3

Add all these together.

3.3 + 3.1 + 4 + 3.1 + 3.6
≈17

4 0

3 years ago