Answer:
Infinite pairs of numbers
1 and -1
8 and -8
Step-by-step explanation:
Let x³ and y³ be any two real numbers. If the sum of their cube roots is zero, then the following must be true:
![\sqrt[3]{x^3}+ \sqrt[3]{y^3}=0\\ \sqrt[3]{x^3}=- \sqrt[3]{y^3}\\x=-y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D%2B%20%5Csqrt%5B3%5D%7By%5E3%7D%3D0%5C%5C%20%5Csqrt%5B3%5D%7Bx%5E3%7D%3D-%20%5Csqrt%5B3%5D%7By%5E3%7D%5C%5Cx%3D-y)
Therefore, any pair of numbers with same absolute value but different signs fit the description, which means that there are infinite pairs of possible numbers.
Examples: 1 and -1; 8 and -8; 27 and -27.
At 200 miles, both company K and company B will pay $150.
In order to solve that, let's call 845 100%, as we're solving it terms of 845. 845 is 100%, then it follows that 8.45 is 1%.
Now we can see how many 8.45's go into 608, which comes out to 71.95266...%, which can be rounded nicely to 72%
The million doesn't matter.
P(picking one defective) = 3/10
P(picking a 2nd defective) = 2/9
P(1 and 2 defective) = 3/10 x 2/9 = 6/90 = 0.066
Second method using combination:
³C₂ / ¹⁰C₂ = 1/15 = 0.066
Divide calories by grams so 161 / 28= 5.75 now you know 1 gram has 5.75 calories so you multiply 5.75 * 12 to get 69. so 12 grams of <span>cashews = 69 calories </span><span />
