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3 years ago

HI CAN SOMEONE PLEASE HELP ME ON THIS ASAPPP , FIND EF AND THEN GE

Mathematics

1 answer:

Feliz [49]3 years ago

6 0

The answer is b. 12

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Solve for x please 4.5x + 11.5 = 8.5x + 3.5

leonid [27]

Answer: have you tried to use photomath?

6 0

3 years ago

Read 2 more answers

The difference of a number times

Hunter-Best [27]

7 x - 5 = 8
7 x = 8 + 5
7 x = 13
x = 13/7

7 ( 13/7) - 5 = 8
91/7 - 35/7 = 56/7
56/7 = 56/7 = 8

5 0

3 years ago

What is the fourth term in the binomial expansion (a+b)^6)

Dafna11 [192]

Answer:

$20a^3b^3$

Step-by-step explanation:

Binomial Series

$(a+b)^n=a^n+\dfrac{n!}{1!(n-1)!}a^{n-1}b+\dfrac{n!}{2!(n-2)!}a^{n-2}b^2+...+\dfrac{n!}{r!(n-r)!}a^{n-r}b^r+...+b^n$

Factorial is denoted by an exclamation mark "!" placed after the number. It means to multiply all whole numbers from the given number down to 1.

Example: 4! = 4 × 3 × 2 × 1

Therefore, the fourth term in the binomial expansion (a + b)⁶ is:

$\implies \dfrac{n!}{3!(n-3)!}a^{n-3}b^3$

$\implies \dfrac{6!}{3!(6-3)!}a^{6-3}b^3$

$\implies \dfrac{6!}{3!3!}a^{3}b^3$

$\implies \left(\dfrac{6 \times 5 \times 4 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}{3 \times 2 \times 1 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}\right)a^{3}b^3$

$\implies \left(\dfrac{120}{6}\right)a^{3}b^3$

$\implies 20a^3b^3$

7 0

2 years ago

Solve for y.

Dmitry [639]

Answer:

y = 5

Step-by-step explanation:

if y = 5 then

(√10-1) -1 = 2

3 - 1 = 2

true

5 0

3 years ago

Read 2 more answers

What is the average of 3/8 + 2/4 + 5/8 + 7/8 + 1 1/8 + 1 5/8 + 1 7/8 + 4

melisa1 [442]

Answer:

1 3/8

Step-by-step explanation:

Well to find the average or the mean we need to add all the numbers,

3/8 + 2/4 + 5/8 + 7/8 + 1 1/8 + 1 5/8 + 1 7/8 + 4

= 11

Then we divide t by the number of numbers in the set.

11 ÷ 8 = 1 3/8

Thus,

the average in the set is 1 3/8.

Hope this helps :)

4 0

3 years ago