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user100 [1]
3 years ago
5

When you solve an equation and you end with a TRUE STATEMENT, the solution set will be:

Mathematics
1 answer:
Stella [2.4K]3 years ago
7 0

Answer:

false

Step-by-step explanation:

You might be interested in
The two figures below, a regular hexagon and a regular pentagon, have the same
lord [1]

Answer:

69

Step-by-step explanation:

Perimeter = sum of all sides of a regular polygon = the number of sides*length of a side

Length of a side of the given regular hexagon = 3x + 5

Perimeter of hexagon = 6(3x + 5) = 6(3x) + 6(5) = 18x + 30

Length of a side of the given regular pentagon = 4x - 1

Perimeter of pentagon = 5(4x - 1) = 5(4x) - 5(1) = 20x - 5

Since we are told that the perimeter of the regular hexagon is the same as that of the regular pentagon, therefore:

18x + 30 = 20x - 5

Solve for x.

Subtract 20x from both sides

18x + 30 - 20x = 20x - 5 - 20x

-2x + 30 = -5

Subtract 30 from both sides

-2x+ 30 - 30 = -5 - 30

-2x = -35

Divide both sides by -2

x = -35/-2

x = 17.5

Length of a side of pentagon = 4x - 1

Plug in the value of x

4(17.5) - 1 = 70 - 1 = 69

length of a side of the pentagon = 69

7 0
4 years ago
A shot-put throw can be modeled using the equation f(x)=-0.0241x^2 + x + 5.5, where x is the distance traveled in feet and y is
Ahat [919]

Answer:

x=-4.91727

x=46.41105

Step-by-step explanation:

3 0
4 years ago
Properties of the normal distribution include?
V125BC [204]

Answer:

Properties of a normal distribution

The mean, mode and median are all equal.

The curve is symmetric at the center (i.e. around the mean, μ).

Exactly half of the values are to the left of center and exactly half the values are to the right.

The total area under the curve is 1.

Step-by-step explanation:

6 0
4 years ago
points E,F and G are plotted on a number line at -1, 2 and 6 respectively. Find the coordinate o f the point that represents the
Maslowich

Answer:  3 is the weighted average

Step-by-step explanation:

A weighted average is sort of like it sounds. - Different data-points are given different weights as far as how much they affect the answer. It's like you had 4 people on a corporation's board and all four get to vote, but their votes count differently. Person A has a vote that counts as 3. Person B has a vote that counts as 2 votes. Persons C & D each have a vote that counts as just one vote. For peron A to get outvoted, all the others must gang up against him.

Okay, back to our actual problem ...

  • point E measures (-1) and has weight 2x weight of F
  • point F has a measure of 2 and no particular stated weight
  • point G measures 6 and has a weight of 3x weight of F

Since we can assign a weight to point F and the other weights will be based on that, let's just keep it simple and give point F a weight of 1.

That gives E a weight of 2, and G a weight of 3.

So, ...

E value times E weight is   (-1)   x   2 = -2

F value times F weight is      2   x   1 =   2

G value times G weight is   6   x   3 = 18

          Sum of (value x weight)  =  18

          Sum of the weights = 2 + 1 + 3 = 6

WE get the weighted average by taking the sum of (value x weight) products (18) and then dividing by the sum of the weights (6).

18/6 = 3, the weighted average

The point at coordinate 3 represents the weighted average.

4 0
2 years ago
Mike has two containers, One container is a rectangular prism with width 2 cm, length 4cm, and height 10cm. The other is a cylin
saul85 [17]

so, we know both the rectangular prism and the cylinder got filled up to a certain height each, the same height say "h" cm.

we know the combined volume of both is 80 cm³, so let's get the volume of each, sum them up to get 80 then.


\bf \stackrel{\stackrel{\textit{volume of a}}{\textit{rectangular prism}}}{V=Lwh}~~ \begin{cases} L=length\\ w=width\\ h=height\\[-0.5em] \hrulefill\\ L=4\\ w=2\\ \end{cases}~\hspace{2em}\stackrel{\textit{volume of a cylinder}}{V=\pi r^2 h}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=1 \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \stackrel{\textit{prism's volume}}{(4)(2)(h)}~~+~~\stackrel{\textit{cylinder's volume}}{(\pi )(1)^2(h)}~~=~~80 \\\\\\ 8h+\pi h=80\implies h(8+\pi )=80\implies h=\cfrac{80}{8+\pi }\implies h\approx 7.180301999

7 0
4 years ago
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