Question

What is the difference A B C D

Answer 1

Answer:

D. $\frac{x-1}{x^2+3x+2}}$

Step-by-step explanation:

The given expression is;

$\frac{x}{x^2+3x+2}-\frac{1}{(x+2)(x+1)}$

This is the same as;

$\frac{x}{(x+2)(x+1)}-\frac{1}{(x+2)(x+1)}$

The denominators are the same.

Subtract the numerators and write one denominator;

$\frac{x-1}{(x+2)(x+1)}}$

Rewrite to get;

$\frac{x-1}{x^2+3x+2}}$