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Dominik [7]
3 years ago
12

Solve the inequality 5x<2x-3

Mathematics
2 answers:
Vanyuwa [196]3 years ago
8 0

Answer:

x<-1

Step-by-step explanation:

mr Goodwill [35]3 years ago
5 0

Answer:

To solve this inequality you need to get x by itself

5x<2x-3 (your first step would be to subtract 2x from each side)

3x<3 ( you then divide 3 to each side to get x by itself)

x<1

Hope this helps ;)

Step-by-step explanation:

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Can you find the probability to each of these answers...
goldfiish [28.3K]

Problem 1

<h3>Answer: 7/10</h3>

-----------------------

Explanation:

The formula we'll use is

P(A or B) = P(A) + P(B)

which only works if A and B are mutually exclusive events.

P(A or B) = P(A) + P(B)

P(A or B) = 7/20 + 7/20

P(A or B) = (7+7)/20

P(A or B) = 14/20

P(A or B) = (7*2)/(10*2)

P(A or B) = 7/10

=========================================================

Problem 2

<h3>Answer:   3/4</h3>

-----------------------

Explanation:

We'll use the same formula as the previous problem.

P(A or B) = P(A) + P(B)

P(A or B) = 3/10 + 9/20

P(A or B) = 6/20 + 9/20

P(A or B) = (6+9)/20

P(A or B) = 15/20

P(A or B) = (3*5)/(4*5)

P(A or B) = 3/4

=========================================================

Problem 3

<h3>Answer:  3/5</h3>

-----------------------

Explanation:

We'll use the same formula as the previous problem.

P(A or B) = P(A) + P(B)

P(A or B) = 7/20 + 1/4

P(A or B) = 7/20 + 5/20

P(A or B) = (7+5)/20

P(A or B) = 12/20

P(A or B) = (4*3)/(4*5)

P(A or B) = 3/5

=========================================================

Problem 4

<h3>Answer:   0</h3>

-----------------------

Explanation:

This time we're asked to find P(A and B), but since the two events are mutually exclusive, this means the probability of both occurring is 0.

Mutually exclusive events cannot happen simultaneously.

An example would be flipping heads and tails at the same time on the same coin.

The info about P(A) and P(B) is not relevant.

7 0
4 years ago
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