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Ivanshal [37]
3 years ago
11

The point (-7, -24) is on the terminal ray of angle θ which is in standard position. A student found the six trigonometric value

s for angle θ. The student’s answers are shown.sin (theta) = StartFraction 24 Over 25 EndFraction. cosine (theta) = negative seven-twenty-fifths. tangent (theta) = negative twenty-four-sevenths. cosecant (theta) = StartFraction 25 Over 24 EndFraction. secant (theta) = negative StartFraction 25 Over 7 EndFraction. cotangent (theta) = negative StartFraction 7 Over 24 EndFraction.
Which value(s) are incorrect?
Mathematics
2 answers:
Viktor [21]3 years ago
6 0

Answer:

sin (theta)

tan (theta)

csc (theta)

cot (theta)

12345 [234]3 years ago
4 0

Answer:

the first one

Step-by-step explanation:

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Answer: -6.5

Step-by-step explanation:

To find the number between them,find their average or mean .

-6 + -7 = -13

-13/2 = -6.5  

The number between them is -6.5

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You need to multiply n by a power of 10 to help you find the fraction?
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Find the nth term of a gp with (a. find term = 5, common ratio = 2​
Rina8888 [55]

Step-by-step explanation:

we know,

tn= a {(r)}^{n - 1}  \\ T5 = a {(2)}^{5 - 1}  \\ t5 = a \times  {2}^{4}  \\  = 16a

Therefore, nth term of a given gp is

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3 years ago
A factory produces 2354 hammers every hour. Which expression can be used to find how many hammers the factory produces in 3 hour
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8 0
3 years ago
Read 2 more answers
2. Carl needs 15 hours longer than Jennifer to paint a room. If they work together, they can complete the job in 4 hours. Explai
nasty-shy [4]

Answer:

Jennifer would complete the job on her own in 5 hours.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}

x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}

\Delta = b^{2} - 4ac

Rates

The together rate is the sum of their separates rate.

We have that:

Jennifer takes x hours to complete the job on her own, so her rate is 1/x.

Carl needs 15 hours longer than Jennifer, that is, 15 + x hours, so his rate is 1/(15+x).

The together rate is 1/4. So

\frac{1}{4} = \frac{1}{x} + \frac{1}{15+x}

\frac{1}{4} = \frac{15 + x + x}{x(15+x)}

\frac{1}{4} = \frac{15 + 2x}{x(15+x)}

Applying cross multiplication.

x^2 + 15x = 4(15 + 2x)

x^2 + 15x = 60 + 8x

x^2 + 7x - 60 = 0

Quadratic equation with a = 1, b = 7, c = -60. So

\Delta = 7^{2} - 4*1*60 = 289

x_{1} = \frac{-7 + \sqrt{289}}{2} = 5

x_{2} = \frac{-7 - \sqrt{289}}{2} = -12

Since the time to complete the job has to be a positive value.

Jennifer would complete the job on her own in 5 hours.

4 0
3 years ago
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