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PIT_PIT [208]
3 years ago
8

What is the equivalent expression to y+ 2/5y

Mathematics
1 answer:
san4es73 [151]3 years ago
5 0

Answer:

7 y /5

Step-by-step explanation:

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in a new clothing store, she charges 21.75 for each sweatshirt she sells. what was the revenue if she sold 51 sweatshirts last m
finlep [7]

Answer:


Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
For brainiest:):):):):):)
eimsori [14]
#1. Step one) we set find what we can multiply by 5 to get 20, so we divide 20 by 5.
20/5 = 4
Step two) we multiply the bottom denominator (8) by 4
8x4=32
Step three) leave the top numerator the same (20) and replace (d) with 32
Answer : 20/32
#2 step one) we divide 14 by 7
14/7 = 2
Step two) divide 10 by 2
10/2=5
Step three) replace z with 5
Answer) 7/5
#3 step one) divide 24 by 8
24/8=3
Step two) divide 21 by 3
21/3 = 7
Step three) replace (x) for (7)
Answer) 7/8
3 0
3 years ago
1/5 ( y + 10 ) ≤ - 25
uranmaximum [27]

Answer:

y≤−135

Step-by-step explanation:

1/5 ( y + 10 ) ≤ - 25

1/5y+2≤−25

1/5y+2−2≤−25−2

1/5y≤−27

5*1/5y≤(5)*(−27)

y≤−135

8 0
3 years ago
If f(x) = -3x - 5 and g(x) = 4x-2, find (f+g)(x)
vodka [1.7K]

Answer:

(f+g)(x) = x - 7

Step-by-step explanation:

it is simple - when adding 2 functions your simply add both expressions. and the result is then the function of the sum.

the same applies also to other arithmetic operations.

-3x -5 + 4x - 2 = x - 7

7 0
3 years ago
Read 2 more answers
Let v be an eigenvector of a matrix A with a corresponding eigenvalue ?=2. Find one solution x of the system Ax=v.
Murljashka [212]

Answer with explanation:

For, a Matrix A , having eigenvector 'v' has eigenvalue =2

 The order of matrix is not given.

It has one eigenvalue it means it is of order , 1×1.

→A=[a]

Determinant [a-k I]=0, where k is eigenvalue of the given matrix.

It is given that,

k=2

For, k=2, the matrix [a-2 I] will become singular,that is

→ Determinant |a-2 I|=0

→I=[1]

→a=2

Let , v be the corresponding eigenvector of the given eigenvalue.

→[a-I] v=0

→[2-1] v=[0]

→[v]=[0]

→v=0

Now, corresponding eigenvector(v), when eigenvalue is 2 =0

 We have to find solution of the system

→Ax=v

→[2] x=0

→[2 x] =[0]

→x=0, is one solution of the system.

5 0
4 years ago
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