<span>Answer:
We'll have to integrate the growth rate with respect to time, without forgetting the amount of area covered at the start.
A = 2010 + â« 8t1/2 dt (as t goes from 0 to 24)
A = 2010 + [(16/3) t3/2] (as t goes from 0 to 24)
A = 2010 + 627 = 2637 acres
We don't integrate the 2010 here because whatever effects of the passing of time have already taken place over that area. We just treat it as a constant and add it to the result of integration.</span>
I got about a 100 numbers on a math website. Good luck.
Thanks! : )
A "learning rate" expresses the ratio of the labor spent on the n-th item to that spent on the (n/2)-th item. That is, the 8th helicopter manufactured took days related by ...
0.8 × (days for 8th) = (days for 16th)
(days for 8th) = (days for 16th)/0.8 = 1.25×(days for 16th)
Then the days for the 4th are 1.25 times that, and the days for the 2nd are 1.25 times the days for the 4th. The days for the first helicopter will be
... 1.25⁴×106.496 days = 260 days
The appropriate choice is
... d. 260
Answer:
The length of the flag is 730 ft and the width is 310 ft
Step-by-step explanation:
<u><em>The correct question is</em></u>
The perimeter of the flag is 2080 ft what is the flags width and length <u>if</u> the length is 420 ft greater than the width
Let
L ----> the length of the flag
W ---> the width of the flag
we know that
The perimeter of the flag (rectangle) is equal to
we have
so
----> equation A
---> equation B
Solve the system by substitution
substitute equation B in equation A
solve for W
<em>Find the value of L</em>
----> 
therefore
The length of the flag is 730 ft and the width is 310 ft
<span>x-y=2y -> x=3y and
3x-40+2y=180 --> 9y-40+2y=180 --> 11y=220 --> y=20, x=60 --> <A=<C=140 degrees, <B=<D=40 degrees.</span>
