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kaheart [24]
3 years ago
10

Madison created two functions: For function A the value of Y is two less than four times the value of X.

Mathematics
2 answers:
tresset_1 [31]3 years ago
8 0

Answer:

b. Function A has a greater rate of change than Function B has

Naddik [55]3 years ago
4 0

Answer:

b. Function A has a greater rate of change than Function B has

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Problem 1 a jar contains blue, red and green balls. the null-hypothesis h0 is that there is 25% percent of red balls. (1) a samp
Norma-Jean [14]
(1) the probability of that happening is .4444.. so on. the jar isnt 25% red balls because 25% of 36 is only 9 and he pulled out 16 red balls. 

I dont know number two sorry.
5 0
3 years ago
PLEASE HELP ME THIS IS DUE TODAY AND I AM DEPRESSED ( uhm look at photo )
Anuta_ua [19.1K]

Answer:

C. 19

B. 47

C. 12

C. 10

C. -8

Step-by-step explanation:

for each equation you take the number given, input it as the value of the variable, and evaluate the equation

hopefully this helps :)

4 0
3 years ago
A class of 20 boys and 15 girls is divided into n groups so that each group has x boys and y girls. Find x, y and n. what values
melamori03 [73]
20 = 2 x 2 x 5
15 = 3 x 5

common divisor (CD) of 20 and 15 is 5 so n should be 5 and each group has 4 boys and 3 girls.

If there are more than one CD, then there are more than one answer.

If they ask for the largest number of groups, greatest common divisor (GCD) will be the answer.
4 0
3 years ago
Rewrite, using the distributive<br> property.<br> 5(2x – 3y) = [?]* - [ ]y
olchik [2.2K]

Answer:

10x-15y

Step-by-step explanation:

So, when they say use the distrubutive property, they basically mean turning this:

a(b+c)

Into this:

ab+ac

So in this case, it would be:

5(2x-3y)

And we will turn it into:

10x-15y

ANother way to think about it is we are multiplying 2x by 5, and -3y by 5. So:

2x*5

=

10x

And

-3y*5

=

-15y

Then we can combine these two:

10x-15y

Hope this helps!

7 0
3 years ago
HI PLEASE HELP ME WITH MY CALCULUS 1 HW? I AM REALLY STUCK. I need help with parts d,e,g.
asambeis [7]

(d) The particle moves in the positive direction when its velocity has a positive sign. You know the particle is at rest when t=0 and t=3, and because the velocity function is continuous, you need only check the sign of v(t) for values on the intervals (0, 3) and (3, 6).

We have, for instance v(1)\approx-0.91 and v(4)\approx0.91>0, which means the particle is moving the positive direction for 3, or the interval (3, 6).

(e) The total distance traveled is obtained by integrating the absolute value of the velocity function over the given interval:

\displaystyle\int_0^6|v(t)|\,\mathrm dt=\int_0^3-v(t)\,\mathrm dt+\int_3^6v(t)\,\mathrm dt

which follows from the definition of absolute value. In particular, if x is negative, then |x|=-x.

The total distance traveled is then 4 ft.

(g) Acceleration is the rate of change of velocity, so a(t) is the derivative of v(t):

a(t)=v'(t)=-\dfrac{\pi^2}9\cos\left(\dfrac{\pi t}3\right)

Compute the acceleration at t=4 seconds:

a(t)=\dfrac{\pi^2}{18}\dfrac{\rm ft}{\mathrm s^2}

(In case you need to know, for part (i), the particle is speeding up when the acceleration is positive. So this is done the same way as part (d).)

6 0
4 years ago
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