Answer:
sd=4
#=^;_/#"
r3dplusesay
k=0
Step-by-step explanation:
3k+6-3=3
3k = 3+3-6
3k = 6-6
3k = 0
k = 0
not a function
D:{-2,0,3,4}
R:{2,-3,1,1,7}
x² + 6x + 1 = 0
a = 1 , b = 6 , c = 1
The answer should be the 3rd one.