Answer:
The frequency of oranges is the classroom is 47.37%.
Step-by-step explanation:
The relative frequency of oranges is the number of oranges divided by the total number of fruits.
We have that:
8 students brought 2 apples each. So there are 8*2 = 16 apples
4 students brought an apple and an orange each. So there are 16 + 4*1 = 20 apples and 4*1 = 4 oranges.
7 students brough 2 oranges each. So there are 4 + 2*7 = 18 oranges.
There are 18 oranges, and 20+18 = 38 fruits in total.
So the frequency of oranges in the classrom is

Answer:
x>14
Step-by-step explanation:
Step 1: Simplify both sides of the inequality.
−4>−2x+24
Step 2: Flip the equation.
−2x+24<−4
Step 3: Subtract 24 from both sides.
−2x+24−24<−4−24
−2x<−28
Step 4: Divide both sides by -2.
−2x−2<−28−2
x>14
Answer:

Step-by-step explanation:
![\sqrt[n]{a^m}=a^\frac{m}{n}\\\\144^\frac{3}{2}=144^{1\frac{1}{2}}=144^{1+\frac{1}{2}}\qquad\text{use}\ a^na^m=a^{n+m}\\\\=144^1\cdot144^{\frac{1}{2}}=144\sqrt{144}=144\cdot12=1728](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5Em%7D%3Da%5E%5Cfrac%7Bm%7D%7Bn%7D%5C%5C%5C%5C144%5E%5Cfrac%7B3%7D%7B2%7D%3D144%5E%7B1%5Cfrac%7B1%7D%7B2%7D%7D%3D144%5E%7B1%2B%5Cfrac%7B1%7D%7B2%7D%7D%5Cqquad%5Ctext%7Buse%7D%5C%20a%5Ena%5Em%3Da%5E%7Bn%2Bm%7D%5C%5C%5C%5C%3D144%5E1%5Ccdot144%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%3D144%5Csqrt%7B144%7D%3D144%5Ccdot12%3D1728)
Answer:
-42, -21, -14, -7, -6, -3, -2, -1, 1, 2, 3, 6, 7, 14, 21, & 42
Step-by-step explanation:
Your answer will be 7.50. What I did was take 1.25 and times it by 6.