Answer:
B) is correct; on average, each bag of candy has a weight that is 2.6 oz different than the mean weight of 5 oz.
To find the mean absolute deviation, we first find the mean. Find the sum of the data points and divide by the number of data points (without the outlier, 21, in it):
(10+3+7+3+4+6+10+1+2+4)/10 = 50/10 = 5
Now we find the difference between each data point and the mean, take its absolute value, and find their sum:
|10-5|+|3-5|+|7-5|+|3-5|+|4-5|+|6-5|+|10-5|+|1-5|+|2-5|+|4-5| =
5+2+2+2+1+1+5+4+3+1 = 26
We now divide this by the number of data points:
26/10 = 2.6
This is a measure of how much each bag of candy varies from the mean.
We are given
total number of friends =6
the cost of one admission is $9.50
now, we can find total cost for admission
total cost for admission= total number of friends*cost of one admission
total cost for admission=6*9.50
we are given
cost for one ride on the Ferris wheel is $1.50
now, we can find total cost for Ferris wheel ride
total cost for Ferris wheel ride= total number of friends*cost of one ride
total cost for Ferris wheel ride=6*1.50
now, we can find total cost
total cost =total cost for admission+total cost for Ferris wheel ride
total cost
now, we can solve it
total cost
total cost
total cost
so, the total cost is $66...........Answer
Answer:
yes
Step-by-step explanation:
this is because we are eliminating the same shape so the same amount of weight from both sides, therefore the mobile still balances
This is rationalising the denominator of an imaginary fraction. We want to remove all i's from the denominator.
To do this, we multiply the fraction by 1. However 1 can be expressed in an infinite number of ways. For example, 1 = 2/2 = 3/3 = 4n^2 / 4n^2 (assuming n is not zero!). Let's express 1 as the complex conjugate of the denominator, divided by the complex conjugate of the denominator.
The complex conjugate of (3 - 2i) is (3 + 2i). Then do what I just said:
4/(3-2i) * (3+2i)/(3+2i) = 4(3+2i)/(3-2i)(3+2i) = (12+8i)/(9-4i^2) = (12+8i)/(9+4) = (12+8i)/13
This is the answer you are looking for. I hope this helps :)
