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3 years ago

What is the square root of 0.0225

Mathematics

2 answers:

ohaa [14]3 years ago

6 0

Answer:

0.15

Step-by-step explanation:

i goog.led it its probably right

photoshop1234 [79]3 years ago

6 0

Answer:

0.15

Step-by-step explanation:

this is the decimal form

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2 years ago

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I need help with the steps. The answer is (5,2)

Elden [556K]

So with this, I will be using the substitution method. With the first equation, substitute (y+3) into the x variable and solve for y:

$y+3+y=7\\2y+3=7\\2y=4\\y=2$

Next, now that we have the value of y, substitute it into either equation to solve for x:

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3 years ago

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1 year ago

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How to bring the polynomial to the standard form p(x) x^2-2x+4) (x^2+2x+4)

saveliy_v [14]

<h3>Solution:</h3>

$\rightarrow\sf((p(x) {x}^{2} + 2x + 4)( {x}^{2} + 2x + 4)) \\ = \sf {ax}^{2} + bx + c \\ = \sf(p(x) {x}^{2} {x}^{2} + p(x) {x}^{2} (2x) + p(x) {x}^{2} \times 4 + 2x \times {x}^{2} + 2x(2x) + 2x \times 4 + {4x}^{2} + 4(2x) + 4 \times 4) \\ = \sf( {x}^{4} p(x) + {2x}^{3} p(x) + {4x}^{2} p(x) + {2x}^{3} + {8x}^{2} + 16x + 16) \\ \rightarrow \large\boxed{\sf\red{{{x}^{4} p(x) + {2x}^{3} p(x) + {4x}^{2} p(x) + {2x}^{3} + {8x}^{2} + 16x + 16}}}$

<h3>Answer:</h3>

$\large\boxed{\sf{\red{{x}^{4} p(x) + {2x}^{3} p(x) + {4x}^{2} p(x) + {2x}^{3} + {8x}^{2} + 16x + 16}}}$

$\color{red}{==========================}$

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