Given that the line passes through two points
(-2,-2) and (x1,y1)
Equation in point slope form is
y-y1 = m(x-x1)
substitute for slope
Hence equation of the line = ![\frac{y2-y1}{x2-x1} =[tex]y-y1 = \frac{-2-y1}{-2-x1}(x-x1)](https://tex.z-dn.net/?f=%5Cfrac%7By2-y1%7D%7Bx2-x1%7D%20%3D%5Btex%5Dy-y1%20%3D%20%5Cfrac%7B-2-y1%7D%7B-2-x1%7D%28x-x1%29)
Since we donot know the value of x1or y1 the equation would contain x1, y1 also as answer.
Answer in point slope form is
![\frac{y2-y1}{x2-x1} =[tex]y-y1 = \frac{-2-y1}{-2-x1}(x-x1)](https://tex.z-dn.net/?f=%5Cfrac%7By2-y1%7D%7Bx2-x1%7D%20%3D%5Btex%5Dy-y1%20%3D%20%5Cfrac%7B-2-y1%7D%7B-2-x1%7D%28x-x1%29)
Answer:
see below
Step-by-step explanation:

and since f(x)=g(x) the same process applies to g(f(x))
Answer:
70cm
Step-by-step explanation:
,
Since, both of the tank posses the same quantity of water then there volume is the same thing
For rectangular base
Volume= (Lenght × breadth × hheight)
If we substitute values
Lenght= 80 cm
Breadth= 70 cm
height= 45 cm
Volume= 80cm × 70cm × 45cm
Volume= 252000cm^3
For square base
Volume= (side)^2 × height
side =60cm.
But volume of square base= volume of
rectangular base
252000cm^3= 60^2 × height
Height= (252000cm^3)/(60^2 )
Height= 70 cm
Hence, the second tank is 70 cm deep