Answer:
h(8q²-2q) = 56q² -10q
k(2q²+3q) = 16q² +31q
Step-by-step explanation:
1. Replace x in the function definition with the function's argument, then simplify.
h(x) = 7x +4q
h(8q² -2q) = 7(8q² -2q) +4q = 56q² -14q +4q = 56q² -10q
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2. Same as the first problem.
k(x) = 8x +7q
k(2q² +3q) = 8(2q² +3q) +7q = 16q² +24q +7q = 16q² +31q
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Comment on the problem
In each case, the function definition says the function is not a function of q; it is only a function of x. It is h(x), not h(x, q). Thus the "q" in the function definition should be considered to be a literal not to be affected by any value x may have. It could be considered another way to write z, for example. In that case, the function would evaluate to ...
h(8q² -2q) = 56q² -14q +4z
and replacing q with some value (say, 2) would give 196+4z, a value that still has z as a separate entity.
In short, I believe the offered answers are misleading with respect to how you would treat function definitions in the real world.
8333/5000 have a brainly day :)
Answer:
there is no quick way around this. U need to plug in -4,2,8 into x value into the function, and see what y returns to
Step-by-step explanation:
Answer:
Step-by-step explanation:
Reduce the expression, if possible, by cancelling the common factors.
0.27
Answer:
C. 55°
Step-by-step explanation:
The computation of mAC is shown below:
Given that
Diameter AB would be parallel to CD
McD = 70
Based on the attached diagram and the above information
mAC is
= (180 - 70) ÷ 2
= 55 degrees
hence, the correct option is third
