a line contains the points (-26, -37) and (-32, -61). What is the slope of the line in simplified form?

Comparing Order of Magnitude A biologist estimated the number of cells in a culture sample as 1.3 × 102. One week later, he look

Assoli18 [71]

Answer:

3 * 10^3 in scientific notation.

3,000 in standard notation.

Step-by-step explanation:

We divide:

3.9 *10^5 / 1.3 * 10^2

= ( 3.9/1.3) * (10^5 / 10^2)

= 3 * 10(5-2)

= 3 * 10^3.

This equals 3 * 1,000 = 3000.

4 0

3 years ago

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Does anyone know the answer to 2

alexdok [17]

The answer is c hope this helps :)

8 0

4 years ago

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Find the area of a circle with a radius of 3

ExtremeBDS [4]

Answer: 28.27

Step-by-step explanation: first multiply the radius by itself 3 times 3 = 9

then take 9 and multiply it by 3.14 which is 28.27

hope this helps mark me brainliest

7 0

3 years ago

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Please help, solve for x

bija089 [108]

Answer:

x=39°

Step-by-step explanation:

the tangent from the diameter is 90°

x+90+51=180 sum of interior angle of the triangle is 180

x=180-90-51=39°

8 0

3 years ago

find the equation in slope intercept form of a line that is a perpendicular bisector of segment AB with endpoints A(-5,5) and B(

aliina [53]

The equation in slope intercept form of a line that is a perpendicular bisector of segment AB with endpoints A(-5,5) and B(3,-3) is y = x + 2

<h3>Solution:</h3>

Given, two points are A(-5, 5) and B(3, -3)

We have to find the perpendicular bisector of segment AB.

Now, we know that perpendicular bisector passes through the midpoint of segment.

The formula for midpoint is:

$\text { midpoint }=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

$Here x_1 = -5 ; y_1 = 5 ; x_2 = 3 ; y_2 = -3$

$\text { So, midpoint of } A B=\left(\frac{-5+3}{2}, \frac{5+(-3)}{2}\right)=\left(\frac{-2}{2}, \frac{2}{2}\right)=(-1,1)$

Finding slope of AB:

$\text { Slope of } A B=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$\text { Slope } m=\frac{-3-5}{3-(-5)}=\frac{-8}{8}=-1$

We know that product of slopes of perpendicular lines = -1

So, slope of AB $\times$ slope of perpendicular bisector = -1

- 1 $\times$ slope of perpendicular bisector = -1

Slope of perpendicular bisector = 1

We know its slope is 1 and it goes through the midpoint (-1, 1)

The slope intercept form is given as:

y = mx + c

where "m" is the slope of the line and "c" is the y-intercept

Plug in "m" = 1

y = x + c ---- eqn 1

We can use the coordinates of the midpoint (-1, 1) in this equation to solve for "c" in eqn 1

1 = -1 + c

c = 2

Now substitute c = 2 in eqn 1

y = x + 2

Thus y = x + 2 is the required equation in slope intercept form

7 0

4 years ago