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Alex
3 years ago
5

Please help, asap! ive tried everything to solve this and everything has been wrong so far.

Mathematics
1 answer:
Vlad1618 [11]3 years ago
6 0

Answer:

Step-by-step explanation:

$575.68

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Mrs. Steward needs to save (4.2 X 10^6) dollars for her children's college education. If she can save (1.4 X 10^2) each month, h
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Answer: 30,000 months or 2,500 years

She'd better start saving more haha.

Step-by-step explanation:

Goal=4.2x10^6\\Savings/month=1.4x10^2

\frac{4.2x10^6}{1.4x10^2} =(\frac{4.2}{1.4})x10^(^6^-^2^)=(3)x10^4=3x10^4 =30000 months=\frac{30000}{12}=2500years

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"What set of reflections would carry hexagon ABCDEF onto itself?. .
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3 years ago
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Why do scientist collect data
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3 years ago
A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along
mina [271]

Answer:

The tip of the man shadow moves at the rate of \frac{20}{3} ft.sec

Step-by-step explanation:

Let's draw a figure that describes the given situation.

Let "x" be the distance between the man and the pole and "y" be distance between the pole and man's shadows tip point.

Here it forms two similar triangles.

Let's find the distance "y" using proportion.

From the figure, we can form a proportion.

\frac{y - x}{y} = \frac{6}{15}

Cross multiplying, we get

15(y -x) = 6y

15y - 15x = 6y

15y - 6y = 15x

9y = 15x

y = \frac{15x}{9\\} y = \frac{5x}{3}

We need to find rate of change of the shadow. So we need to differentiate y with respect to the time (t).

\frac{dy}{t} = \frac{5}{3} \frac{dx}{dt} ----(1)

We are given \frac{dx}{dt} = 4 ft/sec. Plug in the equation (1), we get

\frac{dy}{dt} = \frac{5}{3} *4 ft/sect\\= \frac{20}{3} ft/sec

Here the distance between the man and the pole 45 ft does not need because we asked to find the how fast the shadow of the man moves.

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3 years ago
Vertex form of -x^2-8x-16
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Answer:

y =  - (x + 4)^{2}

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