Answer:
the limit does not exist
Step-by-step explanation:
As x approaches π/2 from below, tan(x) approaches +∞. A x approaches π/2 from above, tan(x) approaches -∞. These two limits are not the same, so the limit is said not to exist.
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For a limit to exist, it must be the same regardless of the direction of approach.
Answer: B
Negative a squared b and 5 a squared b
Step-by-step explanation:
Given that:
Negative a squared b + 6 a b minus 8 + 5 a squared b minus 6 a minus b. That is,
- a^2b + 6ab - 8 + 5a^b - 6a - b
Collecting the like term by rearranging the expression
5a^2b - a^2b + 6ab - 6a - b
The like terms in the expression above are
5a^2b - a^2b.
The correct option is B:
Negative a squared b and 5 a squared b or (-a^2b and 5a^b)
By applying 2×pie×radius (radius+height)
This answer comes 1925000mm^3
Remember you can do anything to an eqautoin as long as you do oit to both sides
-5x=15
try to get 1x by itself
remember
(ax)/a=x when a=a
so
-5x=15
get x
divide both sides by -5
remember to flip sign
(-5x)/(-5)=15/(-5)
x=-3
answer is first one
x=-3
answer
(x+7)^2 + (y-4)^2 = 64
set up equation
the equation of a circle is (x - h)^2 + (y - k)^2 = r^2
where h is the center x coordinate and k is the center y coordinate
values
from the point (-7,4) we know that h = -7 and k = 4
since the radius is 8, r^2 = 8^2 = 64
plug in values
now that we have all the values, we plug them into (x - h)^2 + (y - k)^2 = r^2
(x - h)^2 + (y - k)^2 = r^2
(x - (-7))^2 + (y-4)^2 = 64
(x+7)^2 + (y-4)^2 = 64
