What are all the keys that must be pressed, in correct order, on the calculator shown to find the value of 462 divided by 3?

Evaluate the expression 4^3÷(7-3) × 2 PLEASE HURRY AND HELP ME I DONT HAVE MUCH TIME TILL ITS DUE

docker41 [41]

Answer:

The answer is 32.

Step-by-step explanation:

7 0

2 years ago

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Help I’ll give brainliest

pychu [463]

Answer:

The 5th is correct.

Step-by-step explanation:

The ratio of orange juice (1) to raspberry juice (1) is 1 to 1.

4 0

2 years ago

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How can 17/20 and 7/4 make a sum of 9/10

Anika [276]

Answer:

the answer is $\frac{35}{20}$

Step-by-step explanation:

You have to find the common denominator in order to get the sum.

multiply 5 to $\frac{7}{4}$ and you get $\frac{35}{20}$

then to double check the sum, subtract it.

$\frac{35}{20}-\frac{17}{20}=\frac{9}{10}$

hope this make sense :/

6 0

3 years ago

The bird feeder on a pole measures +6 feet and there is a buried treasure chest at -4 feet. 0 is ground level. Determine which i

Strike441 [17]

the answer is 4

just think of -4 as 4 in this question it is looking for the one closer and now that both of them are counting numbers 4 is less

4 0

2 years ago

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A certain company sends 40% of its overnight mail parcels by means of express mail service A1. Of these parcels, 4% arrive after

Harrizon [31]

Answer:

(a) The probability that a randomly selected parcel arrived late is 0.026.

(b) The probability that a parcel was late was being shipped through the overnight mail service A₁ is 0.615.

(c) The probability that a parcel was late was being shipped through the overnight mail service A₂ is 0.192.

(d) The probability that a parcel was late was being shipped through the overnight mail service A₃ is 0.192.

Step-by-step explanation:

Consider the tree diagram below.

(a)

The law of total probability sates that: $P(A)=P(A|B)P(B)+P(A|B')P(B')$

Use the law of total probability to determine the probability of a parcel being late.

$P(L)=P(L|A_{1})P(A_{1})+P(L|A_{2})P(A_{2})+P(L|A_{3})P(A_{3})\\=(0.04\times0.40)+(0.01\times0.50)+(0.05\times0.10)\\=0.026$

Thus, the probability that a randomly selected parcel arrived late is 0.026.

(b)

The conditional probability of an event A provided that another event B has already occurred is:

$P(A|B)=\frac{P(B|A)P(A)}{P(B)}$

Compute the probability that a parcel was late was being shipped through the overnight mail service A₁ as follows:

$P(A_{1}|L)=\frac{P(L|A_{1})P(A_{1})}{P(L)} \\=\frac{0.04\times 0.40}{0.026} \\=0.615$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₁ is 0.615.

(c)

Compute the probability that a parcel was late was being shipped through the overnight mail service A₂ as follows:

$P(A_{2}|L)=\frac{P(L|A_{2})P(A_{2})}{P(L)} \\=\frac{0.01\times 0.50}{0.026} \\=0.192$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₂ is 0.192.

(d)

Compute the probability that a parcel was late was being shipped through the overnight mail service A₂ as follows:

$P(A_{3}|L)=\frac{P(L|A_{3})P(A_{3})}{P(L)} \\=\frac{0.05\times 0.10}{0.026} \\=0.192$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₃ is 0.192.

4 0

3 years ago