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3 years ago

Rewrite in simplest terms: 3h - 2(-0.1h - 0.8)please help

Mathematics

1 answer:

levacccp [35]3 years ago

8 0

Answer:

3.2h+1.6

Step-by-step explanation:

3h-2(-0.1h-0.8)

3h+0.2h+1.6

3.2h+1.6

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Multiply and simplify the product. (3 – 5i)(–2 + 4i) Select the product.

garri49 [273]

Answer:

-20i^2 + 22i - 6

Step-by-step explanation:

(3 - 5i)(-2 + 4i) = -6 + 10i + 12i - 20i^2 = -20i^2 + 22i - 6

if you want to go further,

-20i^2 + 22i - 6 = -2(10i^2 - 11i + 3)

6 0

3 years ago

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Over a certain region of space, the electric potential is V = 4x − 7x2y + 7yz2. Find the expressions for the x, y, z components

Tju [1.3M]

Answer:

Ex = - 4 + 14xy

Ey = 7x² - 7z²

Ez = -14yz

Step-by-step explanation:

The relationship between Electric field Er(x, y, z) and Electric potential, V, is a differential relationship:

Er(x, y, z) = -dV/dr(x, y, z)

Where r(x, y, z) = distance in x, y and z components.

The x component of the electric field is:

Ex = -dV/dx

Given that:

V = 4x - 7x²y + 7yz²

Ex = -dV/dx

Ex = -(4 - 14xy)

Ex = -4 + 14xy

The y component of the electric field is:

Ey = -dV/dy

Ey = -(-7x² + 7yz²)

Ey = 7x² - 7z²

The z component of the electric field is:

Ez = -dV/dz

Ez = -(14yz)

Ez = -14yz

8 0

3 years ago

A thread of length 52.31 cm is bent to form a circle.

balandron [24]

8.33 bc 52.31 divided by 3.14 = 16.874… and then divided that by two

6 0

2 years ago

Can someone help me out? (serious answers only)

Lerok [7]

Answer:

Step-by-step explanation:

6 0

3 years ago

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Answer too a and b plz don't understand at all

Arisa [49]

Greetings!

Arrange the equation in slope y-intercept form to calculate the rate of change (hourly rate):
$y=mx+b$

Isolate for y:
$45x-3y=-30$

Add -45x to both sides:
$(45x-3y)+(-45x)=(-30)+(-45x)$

$-3y=-45x-30$

Divide both sides by -3:
$\frac{-3y}{-3}= \frac{-45x-30}{-3}$

The Equation Is:
$\boxed{y=15x+10}$

The Hourly Rate (Represented by the slope) is: $15
The Signing Bonus (Represented by the y-intercept) is: $10

<em>The Graph for this Equation is attached below:

</em>I hope this helped!
-Benjamin

8 0

3 years ago