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seropon [69]
3 years ago
5

Please help me with the question please ASAP ASAP please please help ASAP ASAP please please help please

Mathematics
1 answer:
andre [41]3 years ago
6 0

Answer:

x = 15 ft

Step-by-step explanation:

Triangle ACD is similar to triangle ABE based on the information given, therefore we can set up a proportion to compare the sides:

side AE / side EB = side AD / side DC

4/6 = 10/x

Solve for x

x = (10)(6) / 4

x = 60 / 4

x = 15 ft

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3 0
3 years ago
Find the area of the shaded region round to the nearest tenth
Alenkinab [10]

Answer: 818.4

Step-by-step explanation:

Using the area of a sector formula, we get the area of the entire sector is (\pi)(27.8^{2})\left(\frac{150}{360} \right).

Using the formula A=\frac{1}{2} ab \sin C, we get the area of the triangle is \frac{1}{2}(27.8)(27.8)(\sin 150^{\circ}).

So, the area of the shaded sector is (\pi)(27.8^{2})\left(\frac{150}{360} \right)-\frac{1}{2}(27.8)(27.8)(\sin 150^{\circ}) \approx \boxed{818.4}

6 0
2 years ago
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8 0
3 years ago
Find the interquartile range using the following data 4 ,4 , 4 ,4 ,5, 6 ,7 , 7 ,7
katen-ka-za [31]

Answer:

3

Step-by-step explanation:

Ascending order:

4 ,4 , 4 ,4 ,5, 6 ,7 , 7 ,7

9 data: split in

4 ,4 , 4 ,4   |   5   |   6 ,7 , 7 ,7

4 ,4   |   4 ,4   |   5   |   6 ,7   |   7 ,7

(7+7)/2-(4+4)/2

=7-4

=3

7 0
3 years ago
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