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3 years ago

Help please will give brainliest due at 4:00 pm

Mathematics

1 answer:

k0ka [10]3 years ago

8 0

Answer: To me it looks like A or D.

Step-by-step explanation: i would probably go with A because thats the only information it gave. hope this helped :)

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What is 9/16 x 2/3 (show ur work) thanks

Ilya [14]

Answer:

$\displaystyle{ \frac{9}{16} \times \frac{2}{3} }$

$\displaystyle{ \frac{9 \times 2}{16 \times 3} }$

$\displaystyle{ \frac{18}{48} }$

$\displaystyle{ \frac{ \cancel2 \times \cancel3 \times 3}{2 \times \cancel2 \times 2 \times 2 \times \cancel3} }$

$\displaystyle{ \frac{3}{2 \times 2 \times 2} }$

$\displaystyle{ \frac{3}{8} }$

6 0

3 years ago

The value of a car bought new for $28900 decreases 15% each year. Identify the function for the value of the car. Does the funct

Eva8 [605]

Answer:

V (t) = 28,900 - 4,335t

The function clearly represent a decay

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Value of the car = $ 28,900

Annual depreciation = 15% = 0.15

2. Identify the function for the value of the car. Does the function represent growth or decay?

Let y represent the value of the car after t years of utilization, let p the price of the car and d, the annual depreciation, therefore:

V (t) = p - (d * t * p)

Replacing with the values we know:

V (t) = 28,900 - (0.15 * t * 28.900)

V (t) = 28,900 - 4,335t

The function clearly represent a decay.

8 0

4 years ago

What is the answer to -k - (-8k)

g100num [7]

Answer:

if we simplify then the answer is 7k

Step-by-step explanation:

can someone please answer my question from my profile.

4 0

3 years ago

Read 2 more answers

What is the reason for each step in the solution of the equation?

MrRa [10]

3 0

4 years ago

Use Stokes' Theorem to evaluate C F · dr F(x, y, z) = xyi + yzj + zxk, C is the boundary of the part of the paraboloid z = 1 − x

Serggg [28]

I assume $C$ has counterclockwise orientation when viewed from above.

By Stokes' theorem,

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

so we first compute the curl:

$\vec F(x,y,z)=xy\,\vec\imath+yz\,\vec\jmath+xz\,\vec k$

$\implies\nabla\times\vec F(x,y,z)=-y\,\vec\imath-z\,\vec\jmath-x\,\vec k$

Then parameterize $S$ by

$\vec r(u,v)=\cos u\sin v\,\vec\imath+\sin u\sin v\,\vec\jmath+\cos^2v\,\vec k$

where the $z$ -component is obtained from

$1-(\cos u\sin v)^2-(\sin u\sin v)^2=1-\sin^2v=\cos^2v$

with $0\le u\le\dfrac\pi2$ and $0\le v\le\dfrac\pi2$ .

Take the normal vector to $S$ to be

$\vec r_v\times\vec r_u=2\cos u\cos v\sin^2v\,\vec\imath+\sin u\sin v\sin(2v)\,\vec\jmath+\cos v\sin v\,\vec k$

Then the line integral is equal in value to the surface integral,

$\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

$=\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}(-\sin u\sin v\,\vec\imath-\cos^2v\,\vec\jmath-\cos u\sin v\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle-\int_0^{\pi/2}\int_0^{\pi/2}\cos v\sin^2v(\cos u+2\cos^2v\sin u+\sin(2u)\sin v)\,\mathrm du\,\mathrm dv=\boxed{-\frac{17}{20}}$

6 0

3 years ago