All categories

3 years ago

Out of 160 workers surveyed at a company, 37 walk to work.

Mathematics

1 answer:

Sonja [21]3 years ago

5 0

A. 37/100
b. 736. 3300/160 is 20.215
20.215x37 =
736. hope this helped

You might be interested in

What is the smallest integer greater than 92

mylen [45]

After $92$ , we have the following integers,

$93,94,95,...$

The smallest of these integers is $93$

The smallest integer after $92$ is $93$

4 0

3 years ago

Match each value with its formula for ABC.

MariettaO [177]

The solution to the question is:

c is 6 = $\sqrt{a^{2} + b^{2} -2abcosC }$

b is 5 = $\sqrt{a^{2} + c^{2} -2accosB }$

cosB is 2 = $\frac{a^{2} + c^{2} - b^{2} }{2ac}$

a is 4 = $\sqrt{b^{2} + c^{2} -2bccosA }$

cosA is 3 = $\frac{b^{2} + c^{2} -a^{2} }{2bc}$

cosC is 1 = $\frac{b^{2} + a^{2} - c^{2} }{2ab}$

<h3>What is cosine rule?</h3>

it is used to relate the three sides of a triangle with the angle facing one of its sides.

The square of the side facing the included angle is equal to the some of the squares of the other sides and the product of twice the other two sides and the cosine of the included angle.

Analysis:

If c is the side facing the included angle C, then

$c^{2}$ = $a^{2}$ + $b^{2}$ -2ab cos C-----------------1

then c = $\sqrt{a^{2} + b^{2} -2abcosC }$

if b is the side facing the included angle B, then

$b^{2}$ = $a^{2}$ + $c^{2}$ -2accosB-----------------2

b = $\sqrt{a^{2} + c^{2} -2accosB }$

from equation 2, make cosB the subject of equation

2ac cosB = $a^{2}$ + $c^{2}$ - $b^{2}$

cosB = $\frac{a^{2} + c^{2} - b^{2} }{2ac}$

if a is the side facing the included angle A, then

$a^{2}$ = $b^{2}$ + $c^{2}$ -2bccosA--------------------3

a = $\sqrt{b^{2} + c^{2} -2bccosA }$

from equation 3, making cosA subject of the equation

2bcosA = $b^{2}$ + $c^{2}$ - $a^{2}$

cosA = $\frac{b^{2} + c^{2} -a^{2} }{2bc}$

from equation 1, making cos C the subject

2abcosC = $b^{2}$ + $a^{2}$ - $c^{2}$

cos C = $\frac{b^{2} + a^{2} - c^{2} }{2ab}$

In conclusion,

c is 6 = $\sqrt{a^{2} + b^{2} -2abcosC }$

b is 5 = $\sqrt{a^{2} + c^{2} -2accosB }$

cosB is 2 = $\frac{a^{2} + c^{2} - b^{2} }{2ac}$

a is 4 = $\sqrt{b^{2} + c^{2} -2bccosA }$

cosA is 3 = $\frac{b^{2} + c^{2} -a^{2} }{2bc}$

cosC is 1 = $\frac{b^{2} + a^{2} - c^{2} }{2ab}$

Learn more about cosine rule: brainly.com/question/4372174

$SPJ1

4 0

2 years ago

What is the answer to this question 4(5x+30)=100?

Over [174]

Answer: x = -1

Step-by-step explanation: To solve this equation, we start by distributing the 4 through the parentheses on the left side.

So we have 4 times 5x which is 20x and 4 times 30 which is 120.

So our equation now reads 20x + 120 = 100.

Solving from here, we subtract 120 from both sides of the equation and we have 20x = -20 and dividing both sides by 20, we find that <em>x = -1</em>.

4 0

3 years ago

2. Half of Robert's piece of wire is equal to of Maria's wire. The total length of their wires is 10 feet. How much longer is Ro

Aleonysh [2.5K]

Step-by-step explanation:

Given that,

Half of Robert's piece of wire is equal to of Maria's wire i.e.

$\dfrac{R}{2}=M$ ....(1)