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Darina [25.2K]
3 years ago
10

What is the domain of h please help :(((((((​

Mathematics
1 answer:
Olin [163]3 years ago
7 0

Answer:

Domain is X-values

Range is Y-VALUES

domain as follows: -7,-3, -1, 1, and 4

Range as follows: -2,7, 6, and 3

<h2>I think the domain of h is 3</h2>

Step-by-step explanation:

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9+a=23 need to solve this problem​
Pavel [41]

Answer:

a = 14

Step-by-step explanation:

Given

9 + a = 23 ( subtract 9 from both sides )

a = 14

4 0
4 years ago
Read 2 more answers
If a dog has 2,000,000 toys and he gives 900,000 away. Then gets 2,000 more, also looses 2,000,000. He's sad but then also got 5
Sergeu [11.5K]

Answer:

See below.

Step-by-step explanation:

He does not have enough to loose 2,000,000 at that point, so this whole problem is nonsense.

5 0
4 years ago
If f(x)= 10 sin(x) – 3 then f (30%) = ?
marissa [1.9K]

Answer:

The value of f(30) is equal to 2.

Step-by-step explanation:

The given expression is :

f(x)= 10 \sin(x) - 3

We need to find the value of f(30)

Put x = 30 in above expression.

So,

f(x)= 10 \sin(30) - 3\\\\=10\times \dfrac{1}{2}-3\\\\=5-3\\\\=2

Hence, the value of f(30) is equal to 2.

5 0
3 years ago
Oscar invests $20,000 in three investments earning 6% ,8% and 10%. He invests $9000 more in the 10% investment than in the 6% in
Hatshy [7]
This problem is mainly concerned with setting up an equation.

let's add the interest rates times their respective investment amounts:

a = (9000 + x)0.10

b = x \times 0.06

c=(20000 - ((9000 + x) + x)) 0.08

simplify:

c = (11000 - 2x) \times 0.08

sum of interest:

1780 = a + b + c

1780 = (9000+x) 0.10 + x 0.06 + (11000-2x)0.08

1780 = 1780 + 0 \times x

0=0

solution:

He does not have any invested in the 6%, while he has 9000 invested at 10% and 11,000 invested at 8%

to check:

9000 \times 0.10 + 11000 \times 0.08

= 900 + 880 = 1780

So this ended up being a trick problem because he does not actually have any invested in the 6% option.
6 0
3 years ago
A data set lists earthquake depths. The summary statistics are nequals300​, x overbarequals5.89 ​km, sequals4.44 km. Use a 0.01
kirza4 [7]

Answer:

Null hypothesis H_0:\mu=5.00km

Alternative hypothesis H_1:\mu\neq 5.00km

The p value is 0.000517, which is less than the significance level 0.01, therefore we reject the null hypothesis and conclude that population mean is not equal to 5.00.

Step-by-step explanation:

It is given that a data set lists earthquake depths. The summary statistics are

n=300

\overline{x}=5.89km

s=4.44km

Level of significance = 0.01

We need to test the claim of a seismologist that these earthquakes are from a population with a mean equal to 5.00.

Null hypothesis H_0:\mu=5.00km

Alternative hypothesis H_1:\mu\neq 5.00km

The formula for z-value is

z=\frac{\overline{x}-\mu}{\frac{s}{\sqrt{n}}}

z=\frac{5.89-5.00}{\frac{4.44}{\sqrt{300}}}

z=\frac{0.89}{0.25634351952}

z=3.4719

The p-value for z=3.4719 is 0.000517.

Since the p value is 0.000517, which is less than the significance level 0.01, therefore we reject the null hypothesis and conclude that population mean is not equal to 5.00.

6 0
3 years ago
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