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Darina [25.2K]
3 years ago
10

What is the domain of h please help :(((((((​

Mathematics
1 answer:
Olin [163]3 years ago
7 0

Answer:

Domain is X-values

Range is Y-VALUES

domain as follows: -7,-3, -1, 1, and 4

Range as follows: -2,7, 6, and 3

<h2>I think the domain of h is 3</h2>

Step-by-step explanation:

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1.6y+y-4/15y+1 1/6y=2 1/3<br><br> PLZ HELP I GIVE BRAINLYIEST TO WHOEVER SOLVES FIRST
Andrej [43]

Answer:

i think its 2/3

Step-by-step explanation:

5 0
3 years ago
In the picture below, ABCD is a rectangle. If the area of triangle ABE is 40, what is the area of the triangle?
MariettaO [177]

Area of the rectangle: 112

Step-by-step explanation:

Picture is missing: find it in attachment.

The area of a triangle is given by

A=\frac{1}{2}bh

where

b is the length of the base

h is the height

For triangle ABE, we know that

A = 40 (area)

h = 8 (height)

So we can find the length of the base AE:

AE=b=\frac{2A}{h}=\frac{2(40)}{8}=10

Now we observe that the base of the rectangle, AD, is the sum of AE and DE, therefore:

AD=AE+DE=10+4=14

We also know the height of the rectangle AB is 8, and that the area of a rectangle is

A=bh

where b is the base and h the height. Therefore, the area of this rectangle is

A=bh=(AD)(AB)=(14)(8)=112

Learn more about area of figures:

brainly.com/question/4599754

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7 0
4 years ago
Can someone help me?
juin [17]

Answer:

5/12

Step-by-step explanation:

8 0
3 years ago
According to DeMorgan 's theorem, the complement of W · X + Y · Z is W' + X' · Y' + Z'. Yet both functions are 1 for WXYZ = 1110
sergeinik [125]

Answer:

The parenthesis need to be kept intact while applying the DeMorgan's theorem on the original equation to find the compliment because otherwise it will introduce an error in the answer.

Step-by-step explanation:

According to DeMorgan's Theorem:

(W.X + Y.Z)'

(W.X)' . (Y.Z)'

(W'+X') . (Y' + Z')

Note that it is important to keep the parenthesis intact while applying the DeMorgan's theorem.

For the original function:

(W . X + Y . Z)'

= (1 . 1 + 1 . 0)

= (1 + 0) = 1

For the compliment:

(W' + X') . (Y' + Z')

=(1' + 1') . (1' + 0')

=(0 + 0) . (0 + 1)

=0 . 1 = 0

Both functions are not 1 for the same input if we solve while keeping the parenthesis intact because that allows us to solve the operation inside the parenthesis first and then move on to the operator outside it.

Without the parenthesis the compliment equation looks like this:

W' + X' . Y' + Z'

1' + 1' . 1' + 0'

0 + 0 . 0 + 1

Here, the 'AND' operation will be considered first before the 'OR', resulting in 1 as the final answer.

Therefore, it is important to keep the parenthesis intact while applying DeMorgan's Theorem on the original equation or else it would produce an erroneous result.

3 0
3 years ago
There are 10 pill bottles. 9 bottles are full of non-poisonous pills and there is one bottle full of poisonous pills. The non-po
Fudgin [204]

Answer: open all the bottles count the pills or ask in each bottle the 1 ounce will have 1 less then all of the 1.1 ounce

Step-by-step explanation:

8 0
3 years ago
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