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Lyrx [107]
3 years ago
12

Which graph best represents a system of equations that has no solution?

Mathematics
1 answer:
olasank [31]3 years ago
6 0

Answer:

D

Step-by-step explanation:

A system of equations with no solution means the lines are parallel and never intersect.

The only graph showing a possible set of parallel lines is D

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Which option summarizes what gave Chandra Gupta I power
mars1129 [50]

Answer:

Chandra Gupta I, King of India reigned from 320 to about 330 CE and founder of the Gupta empire. He was the grandson of Sri Gupta, the first known leader of the Gupta line. Chandra Gupta I, whose first life is unknown, became the local chief of the kingdom of Magadha parts of the modern state of Bihar.

Step-by-step explanation:

6 0
3 years ago
You notice a hot air balloon descending. The elevation h
ANEK [815]

Answer:

the domain is 0 x 45 and the range is 0 h 360. The slope is -8, so the change in the height of the ballon is -8 feet per second. The h-intercept is 360, so the height of the ballon when the first noticed it was 360 feet. The x-intercept is 45, so the time it took the hot air balloon to reach the ground was 45 seconds.

Step-by-step explanation:

8 0
3 years ago
Identify a pattern by making a table of the inputs and outputs.
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it wants you to make a table of the inputs and out puts, and what is the pattern that is happening. like is it a constant increase/decrease and things like that. i'll help you on the table...

x | y

1 | 5

2 | 4

3 | 3

4 | 2

(i am not sure what that 40 is at the end, but You get the point)

now all you have to do is identify the sequence or pattern you see here


3 0
3 years ago
A candy store sells 2 ounces of chocolate for $0.80 and 3 ounces of chocolate for $0.90. How much does the store charge per ounc
Arte-miy333 [17]
Divide the 2 ounces into the .80 which would be 0.40 per ounce for the 2 ounces chocolate and divide the 3 ounces into the .90 which would be 0.30 per ounce for the 3 ounces of chocolate
4 0
3 years ago
Find the area of the shaded region round to the nearest tenth
Alenkinab [10]

Answer: 818.4

Step-by-step explanation:

Using the area of a sector formula, we get the area of the entire sector is (\pi)(27.8^{2})\left(\frac{150}{360} \right).

Using the formula A=\frac{1}{2} ab \sin C, we get the area of the triangle is \frac{1}{2}(27.8)(27.8)(\sin 150^{\circ}).

So, the area of the shaded sector is (\pi)(27.8^{2})\left(\frac{150}{360} \right)-\frac{1}{2}(27.8)(27.8)(\sin 150^{\circ}) \approx \boxed{818.4}

6 0
2 years ago
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