Given:
Budget = $30
cost of pizza = $9
cost of drinks = $1
number of pizza = p
number of drinks = d

pizza and drinks should only be equal to or less than the budget of $30.

$9p + $1d < $30

unit cost of pizza : 9
unit cost of drinks : 1
total cost of set (p & d) 10

pizza = 9/10 x 30 = 27 total cost of pizza
drinks =1/10 x 30 = 3 total cost of drinks

27 ÷ 9 = 3 number of pizzas to order
3 ÷ 1 = 3 number of drinks to order

To check:

9p + 1d < 30
9(3) + 1(3) < 30
27 + 3 < 30
30 < 30

6 0

4 years ago

If rain is falling at a rate of 1/4 inch per hour, how much rain would you expect after 6 hours?

serg [7]

I think its 1.5 but im not sure 100%

5 0

4 years ago

Read 2 more answers

In a restaurant, the proportion of people who order coffee with their dinner is p. A simple random sample of 144 patrons of the

mote1985 [20]

<h2>Answer with explanation:</h2>

Given : In a restaurant, the proportion of people who order coffee with their dinner is p.

Sample size : n= 144

x= 120

$\hat{p}=\dfrac{x}{n}=\dfrac{120}{144}=0.83333333\approx0.8333$

The null and the alternative hypotheses if you want to test if p is greater than or equal to 0.85 will be :-

Null hypothesis : $H_0: p\geq0.85$ [ it takes equality (=, ≤, ≥) ]

Alternative hypothesis : $H_1: p$ [its exactly opposite of null hypothesis]

∵Alternative hypothesis is left tailed, so the test is a left tailed test.

Test statistic : $z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

$z=\dfrac{0.83-0.85}{\sqrt{\dfrac{0.85(1-0.85)}{144}}}\\\\=-0.561232257678\approx-0.56$

Using z-vale table ,

Critical value for 0.05 significance ( left-tailed test)=-1.645

Since the calculated value of test statistic is greater than the critical value , so we failed to reject the null hypothesis.

Conclusion : We have enough evidence to support the claim that p is greater than or equal to 0.85.

8 0

3 years ago

A reflection across the x-axis keeps the x-coordinate the same but flips the y-coordinate. What do you think a reflection across

Studentka2010 [4]

Answer: A reflection across the x-axis keeps the x-coordinates the same but flips the signs of the y-coordinates. So, it should be the opposite for a reflection across the y-axis. The y-coordinates remain the same, but the signs of the x-coordinates change.

Step-by-step explanation

I copy and pasted the answer

8 0

3 years ago