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SIZIF [17.4K]
2 years ago
14

Identify the triangle by its sides and angles:

Mathematics
1 answer:
navik [9.2K]2 years ago
4 0

Answer: Right and isosceles

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A flying squirrel lives in a nest that is 15 feet high in a tree. To reach a fallen acorn that is 8 feet from the base of the tr
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He will have to fly 23 feet, 15 feet down and 8 feet to the acorn
4 0
2 years ago
Find the surface area of the sphere.
fenix001 [56]

Answer:

804 in^2

Step-by-step explanation:

The surface area of a sphere is given by A = 4πr^2, where r is the radius of the sphere.

Here, A = 4π*8^2 in^2 (must use units of measurement)

              =256π in^2, or approximately 804 in^2

4 0
3 years ago
Read 2 more answers
If a scale distance of 3.5 inches on a map represent an actual distance of 175 km what actual distance does a scale distance of
gavmur [86]

Considering the definition of map and scale, an actual distance of 269.59 km represent a scale distance of 5.7 inches .

<h3>Definition of map and scale</h3>

A map is a representation of a place, at a size smaller than the real size.

The scale of a cartographic representation is the relationship of similarity between the real dimensions of the geographical space represented and those of its image on the map. That is, the scale is defined as the proportionality relationship that exists between a distance measured on the ground and its corresponding measurement on the map.

One way to represent the scale is by a fraction, which indicates the proportion between the distance on a map and its corresponding distance in reality:

Scale=\frac{distance on the map}{distance in reality}

<h3>Actual distance in this case</h3>

In this case, you know that a scale distance of 3.5 inches on a map represent an actual distance of 175 km.

To know the real distance that represents a scale distance of 5.7 inches, as the scale ratio is the same as in the previous case, it is expressed:

\frac{3.7 inches}{175 km}=\frac{5.7 inches}{distance in reality}

Solving:

\frac{3.7 inches}{175 km}×distance in reality= 5.7 inches

distance in reality= \frac{5.7 inches}{\frac{3.7 inches}{175 km}}

<u><em>distance in reality= 269.59 km</em></u>

In summary, an actual distance of 269.59 km represent a scale distance of 5.7 inches .

Learn more about map and scale:

brainly.com/question/24693076

brainly.com/question/13150795

brainly.com/question/27928319

#SPJ1

8 0
1 year ago
Factor out 3^2 ^3−18^2 ^4
34kurt
The factor of three is six factor of two is to 3 is three factor of two is 22 is four and poster of four is 22 Answer
3 0
3 years ago
How do the average rates of change for f(x) = -0.5x² and g(x) = -1.5x² over the interval -5 ≤ x ≤ -2 compare?​
masha68 [24]
Pick an x-value between the interval givens. I’ll choose “1”. If you sub in one for both f(x) and g(x) you get that f(1) = -1.5 and g(1) = -0.5. Now you can divide f(1) by g(1) to get average rate of change. -1.5/-0.5 = 3.
8 0
2 years ago
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