Since x=8y, subsitute 8y for x in other equation
y=6x-11
y=6(8y)-11
y=48y-11
minus y both sides
0=47y-11
add 11 to both sides
11=47y
divide both sides by 47
subsitute taht for y to find x
x=8y
in (x,y) form
(x,y)
10%of30=3
3x4=12
A. 40%of 30=12 senior class members.
B. 60% of the class were not senior class members
start with the ones and every time it goes over ten take the first number and add it to the tens for example 1+8+4+8=21 take the one and put it in the one spot below. Then take the 2 and add it to the six in the tens spot so it would be Instead of 6+8+3+2 it would be 8+8+3+2 which would equal 21 then put the 1 u=in the ten spot below add the 2 to the hundreds spot making is 5+5+7=4=14 put the 4 Below and add the 1 the the thousands making it 3+4+5+1=13 put the one on the ten thousands and put the three below the whole problem would be 13,411.
Answer:
The answer would most likely A.
Step-by-step explanation:
In Euclidean geometry, a regular polygon is a polygon that is equiangular (all angles are equal in measure) and equilateral (all sides have the same length). Regular polygons may be either convex or star. Most of the polygons sides are equal.
A polygon has the same number of sides and angles because they are closed figures with non-intersecting lines. Meaning, it would be the correct answer of A.
(If I'm correct, may I have brainliest?)
(If I'm wrong, please correct me.)
