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wariber [46]
1 year ago
9

Usqqe format HTH to mean that the first toss is heads, the second is tails and the third is heads more than one element in the s

et, separate them with commas

Mathematics
1 answer:
Scrat [10]1 year ago
4 0

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: State the number of outcomes possible for three tossing of a coin

Since a coin has two possible outcomes and is tossed three times, the total outcomes will be:

\begin{gathered} 2^3=8 \\ 8\text{ outcomes} \end{gathered}

STEP 2: Find the number of sample spaces for the three tosses

STEP 3: Get the outcomes of the events for which the second toss is tails

Hence, the answers are given as:

Sample Space:

\lbrace HHH,HHT,HTH,HTT,THH,THT,TTH,TTT\rbrace

The event that the second toss is tails:

\lbrace HTH,HTT,TTH,TTT\rbrace

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It is desired to pile some logs in layers so that the top layer contains one log, the next layer contains two logs, the next lay
Hitman42 [59]

Answer:

Yes all of the logs can be used in such a grouping.

We'll have <u>19 logs</u> in the bottom row (and have 19 rows)

========================================================

Explanation:

Let n be the number of layers. Let T(n) represent how many logs there are total.

  • If you have 1 layer, then you have 1 log. So we can say that T(1) = 1.
  • If there are n = 2 layers, then we have 1 log on top of two other logs, which leads to 1+2 = 3 logs total. This shows that T(2) = 3.
  • If there are n = 3 layers, then we have 1 log on top of 2 which are on top of 3 at the very bottom. We have 1+2+3 = 6 logs total. So T(3) = 6.
  • Having n = 4 layers gives 1+2+3+4 = 10 logs. So T(4) = 10
  • Having n = 5 layers gives 1+2+3+4+5 = 15 logs. So T(5) = 15

This process continues for however long you like. The sequence 1,3,6,10,15 is the set of triangular numbers, since the logs form a triangular or pyramid shape when stacked this way. To get the nth value in the triangular number sequence, use this formula

T(n) = 0.5*n*(n+1)

---------------

For example, let's say we wanted to find how many logs there were in the fifth layer

T(n) = 0.5*n*(n+1)

T(5) = 0.5*5*(5+1)

T(5) = 15

This matches from earlier.

The purpose of bringing in a formula is to see if we can get T(n) = 190 for some integer n.

-------------------

T(n) = 0.5*n*(n+1)

190 = 0.5*n*(n+1)

190*2 = n(n+1)

380 = n^2+n

0 = n^2+n-380

n^2+n-180 = 0

Applying the quadratic formula will lead to the two solutions: n = -20 and n = 19. We ignore the negative value of n as we can't have a negative number of rows. Therefore, n = 19 is the only valid solution here.

If we wanted to stack 190 logs in this triangular pyramid fashion, then we'll need to have 19 rows. The bottom row will have 19 logs.

----------

Check:

1+2+3+4+5+6+7+8+9+10 = 55

11+12+13+14+15+16+17+18+19 = 135

55+135 = 190

Or you could say,

T(n) = 0.5*n*(n+1)

T(19) = 0.5*19*(19+1)

T(19) = 190

Either way, the answer is confirmed.

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Dividing by a fraction is the same as multiplying by its reciprocal. In other words, we can change the divison sign to multiplication and flip the second fraction.

So here, 2/3 ÷ 1/4 can be rewritten as 2/3 × 4/1.

Now we are simply multiplying fractions so we multiply across the numerators or top number number and multiply across the denominators or bottom numbers.

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8/3 can be converted into a mixed number by dividing the denominator of the fraction into the numerator of the fraction.

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