Answer:
C) 7,500 m/s
Explanation:
The satellite's acceleration due to gravity equals its centripetal acceleration.
v² / r = GM / r²
Solving for velocity:
v² = GM / r
v = √(GM / r)
Given:
G = 6.67×10⁻¹¹ m³/kg/s²
M = 5.98×10²⁴ kg
r = 6.357×10⁶ m + 6.8×10⁵ m = 7.037×10⁶ m
Substituting the values:
v = √(6.67×10⁻¹¹ × 5.98×10²⁴ / 7.037×10⁶)
v = √(5.67×10⁷)
v = 7500 m/s
Answer:
541.14 m/s
Explanation:
We are given that
Mass of cannon=
Mass of shell,
Initial velocity of shell,v=547 m/s
We have to find the velocity of shell fired from this loose cannon.
According to law of conservation of momentum
Initial momentum of system=0
When the cannon is bolted to the ground then only shell moves and kinetic energy of system equals to kinetic energy of shell
Kinetic energy of shell,
K.E of shell=
K.E of shell=
K.E of shell=
2K.E of shell=
Velocity of shell fired from this loose cannon,v_2=
Hence, the velocity of shell fired from this loose cannon would be 541.14 m/s
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