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lana [24]
2 years ago
13

What is a geostationary satellite​

Physics
1 answer:
LuckyWell [14K]2 years ago
7 0

Answer:

See below

Explanation:

Geostationary satellites are placed in orbit above the equator at an orbital altitude of  35786 km in order to perfectly match the earth's rotation...thus they APPEAR stationary in the sky ..... then your DISH TV antenna (etc)  can point in one direction at them for continuous communication.    Or.... a spy or weather  satellite would be able to look at one section of the earth non-stop

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1:A pattern or grouping of stars that people imagine representing a figure, an animal or an object.
Nesterboy [21]

Answer:

  • 1.constellation
  • 2.Probably a dwarf planet
7 0
3 years ago
A U-shaped tube open to the air at both ends contains some mercury. A quantity of water is carefully poured into the left arm of
Gekata [30.6K]

Answer:

a) P=2450\ Pa

b) \delta h=23.162\ cm

Explanation:

Given:

height of water in one arm of the u-tube, h_w=25\ cm=0.25\ m

a)

Gauge pressure at the water-mercury interface,:

P=\rho_w.g.h_w

we've the density of the water =1000\ kg.m^{-3}

P=1000\times 9.8\times 0.25

P=2450\ Pa

b)

Now the same pressure is balanced by the mercury column in the other arm of the tube:

\rho_w.g.h_w=\rho_m.g.h_m

1000\times 9.8\times 0.25=13600\times 9.8\times h_m

h_m=0.01838\ m=1.838\ cm

<u>Now the difference in the column is :</u>

\delta h=h_w-h_m

\delta h=25-1.838

\delta h=23.162\ cm

7 0
3 years ago
Determine the angular velocity ω of the telescope as it orbits around the Sun.
lara31 [8.8K]
The JWST is postioned about 1.5 million kilometers from the earth on the side facing away from the sun
5 0
3 years ago
More Density Graphi Questions
nata0808 [166]

Answer:

?

Explanation:

6 0
3 years ago
A youngster having a mass of 50.0 kg steps off a 1.00 m high platform. If she keeps her legs fairly rigid and comes to rest in 1
attashe74 [19]

The average act on her during the deceleration is 4.47 meters per second.                                                                

<u>Explanation</u>:

<u>Given</u>:

youngster mass m = 50.0 kg

She steps off a 1.00 m high platform that is s = 1 meter

She comes to rest in the 10-meter second

<u>To Find</u>:

The average force and momentum

<u>Formulas</u>:

p = m * v

F * Δ t = Δ p

vf^2= vi^2+2as

<u>Solution</u>:

a = 9.8 m/s

vi = 0

vf^2= 0+2(9.8)(1)

vf^2 = 19.6

vf = 4.47 m/s .

Therefore the average force is 4.47 m/s.                                          

                                 

5 0
3 years ago
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