What is a geostationary satellite
1 answer:
You might be interested in
Answer:
10. True. vA = - ¼ vB , pA = - pB
Explanation:
Let us propose the solution of this problem, as the cars are released let us use the conservation of the moment.
Initial before releasing the cars
p₀ = 0
Final after releasing cars
= mA vA + mB vB
p₀ =
0 = mA vA + mB vB
vA = - mB / mA vB
They indicate that mA = 4 mB
vA = - ¼ vB
Let's write the amount of movement for each body
pA = mA vA = 4 mB (- ¼ vB
pA = -mB vB
pB = mB vB
pA = - pB
Let's check the answers
1 False
2 False
3 False
4 false
5 False
6 False
7 False
8 False
9 False
10. True. The speed and amount of movement values are correct
Explanation:
Below is an attachment containing the solution.
Answer:
Car travel a distance of 60.06 m in 6 sec
Explanation:
We have given initial velocity v = 20 m/sec
Time = 6 sec
As the car stops finally so final velocity v = 0
From the first equation of motion
v = u+at (as the car velocity is slows down means it is a case of deceleration)
So v = u-at
Now from second equation of motion