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Pavlova-9 [17]
2 years ago
7

A data set is made up of these values three, three, four, six, six, seven, 10.

Mathematics
1 answer:
Gnoma [55]2 years ago
4 0

Answer:

D

Step-by-step explanation:

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The graphs below are both absolute value functions. The equation of the redgraph is f(x) = |xl. Which of these is the equation o
grigory [225]

ANSWER

\Rightarrow y=\frac{1}{2}|x|

EXPLANATION

We want to find the absolute value function for the line in blue.

The general form of an absolute value function is:

y=a|x-h|+k

where (h, k) = vertex

From the line, the vertex of the graph in blue is:

(0,0)

To find a, we have to pick a point (x, y) on the line and input it into the general function.

Let us pick (2, 1).

Therefore, we have:

\begin{gathered} 1=a|2-0|+0 \\ 1=a|2|=2a \\ \Rightarrow a=\frac{1}{2} \end{gathered}

Therefore, the absolute value function is:

\begin{gathered} y=\frac{1}{2}|x-0|+0 \\ \Rightarrow y=\frac{1}{2}|x| \end{gathered}

3 0
1 year ago
Alonzo is saving money to buy a game. So far he has saved $30 , which is two-thirds of the total cost of the game. How much does
Andrei [34K]
Well, it should be 45 because 1/3 of the game would be 15 and 15+15 is 30 (2/3rds cost), so 15+15+15, 45, would be the full cost of the game
7 0
3 years ago
Common ratio of fraction in geometric sequence? <br> 5/12,-1/6,1/15,-2/75,4/375
mestny [16]
To find the common ratio, u take ur 2nd term, and divide it by ur 1st term
(-1/6) / (5/12) =
-1/6 * 12/5 =
- 2/5 <== ur common ratio
6 0
3 years ago
Suppose it is known that 60% of radio listeners at a particular college are smokers. A sample of 500 students from the college i
vladimir1956 [14]

Answer:

The probability that at least 280 of these students are smokers is 0.9664.

Step-by-step explanation:

Let the random variable <em>X</em> be defined as the number of students at a particular college who are smokers

The random variable <em>X</em> follows a Binomial distribution with parameters n = 500 and p = 0.60.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

1. np ≥ 10

2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=500\times 0.60=300>10\\n(1-p)=500\times(1-0.60)=200>10

Thus, a Normal approximation to binomial can be applied.

So,  

X\sim N(\mu=600, \sigma=\sqrt{120})

Compute the probability that at least 280 of these students are smokers as follows:

Apply continuity correction:

P (X ≥ 280) = P (X > 280 + 0.50)

                   = P (X > 280.50)

                   =P(\frac{X-\mu}{\sigma}>\frac{280-300}{\sqrt{120}}\\=P(Z>-1.83)\\=P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that at least 280 of these students are smokers is 0.9664.

8 0
3 years ago
What can you multiply to give you -42 and add up to 1
yanalaym [24]
-6 + 7 = 1 and -6*7 = -42

So f(x) = (x + 7)(x - 6)
7 0
3 years ago
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