Answer:
Step-by-step explanation:
"When 200 gallons of oil were removed from a tank" algebraically looks like this:
V - 200.
"...the volume of oil left in the tank was 3/7 of the tank's capacity" algebraically looks like this:
3/7(V)
Therefore, the equation is
V - 200 = 3/7(V)
Begin by multiplying both sides by 7:
7(V - 200) = 3V and
7V - 1400 = 3V so
-1400 = -4V so
V = 350 gallons
That's if the volume of the oil in the tank was 3/7 of the tank's capacity.
For the other part of the problem, we set up the equation almost the same, except the 3/7 is a 1/2:
V - 200 = 1/2(V)
Multiplying both sides by 2 gives you
2(V - 200) = V and
2V - 400 = V so
-400 = -V so
V = 400
Step-by-step explanation:
Since AD bisects BC,
BD = DC.
Therefore 5x - 10 = 3x + 10 and x = 10.
Answer: v = u= 
Step-by-step explanation:
v= cos45 * 4=
- Apply Pythagorean theorem
= 
We have u =
rectangular base= 6*10= 60cm^2
big triangles = 12*5=60, 60*2=120cm^2
small triangles= 12.6*3=37.8, 37.8*2=75.6cm^2
add = 255.6 cm^2
Answer:
The lower class boundary for the first class is 140.
Step-by-step explanation:
The variable of interest is the length of the fish from the North Atlantic. This variable is quantitative continuous.
These variables can assume an infinite number of values within its range of definition, so the data are classified in classes.
These classes are mutually exclusive, independent, exhaustive, the width of the classes should be the same.
The number of classes used is determined by the researcher, but it should not be too small or too large, and within the range of the variable. When you decide on the number of classes, you can determine their width by dividing the sample size by the number of classes. The next step after getting the class width is to determine the class intervals, starting with the least observation you add the calculated width to get each class-bound.
The interval opens with the lower class boundary and closes with the upper-class boundary.
In this example, the lower class boundary for the first class is 140.
