Consider the function f (x) = StartLayout Enlarged left-brace first row negative StartFraction x + 5 Over x + 3 EndFraction, x l
ess-than negative 2 second row x cubed + 6, x greater-than-or-equal-to negative 2 EndLayout.
Which statement describes whether the function is continuous at x = –2?
The function is continuous at x = –2 because f(–2) exists.
The function is continuous at x = –2 because Limit as x approaches negative 2 plus f(x) = f(–2).
The function is not continuous at x = –2 because Limit as x approaches negative 2 f(x) ≠ f(–2).
The function is not continuous at x = –2 because Limit as x approaches negative 2 f(x) does not exist.
Which statement describes whether the function is continuous at x = –2?
The function is continuous at x = –2 because f(–2) exists.
The function is continuous at x = –2 because Limit as x approaches negative 2 plus f(x) = f(–2).
The function is not continuous at x = –2 because Limit as x approaches negative 2 f(x) ≠ f(–2).
The function is not continuous at x = –2 because Limit as x approaches negative 2 f(x) does not exist.
1 answer:
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Look at the picture.
Therefore we have the equation:
10y - 29 = 7y + 19 <em>add 29 to both sides</em>
10y = 7y + 48 <em>subtract 7y from both sides</em>
3y = 48 <em>divide both sides by 3</em>
y = 16
3x + 7 = 5x - 21 <em>subtract 7 from both sides</em>
3x = 5x = -28 <em>subtract 5x from both sides</em>
-2x = -28 <em>divide both sides by (-2)</em>
x = 14
