Consider the function f (x) = StartLayout Enlarged left-brace first row negative StartFraction x + 5 Over x + 3 EndFraction, x l
ess-than negative 2 second row x cubed + 6, x greater-than-or-equal-to negative 2 EndLayout.
Which statement describes whether the function is continuous at x = –2?
The function is continuous at x = –2 because f(–2) exists.
The function is continuous at x = –2 because Limit as x approaches negative 2 plus f(x) = f(–2).
The function is not continuous at x = –2 because Limit as x approaches negative 2 f(x) ≠ f(–2).
The function is not continuous at x = –2 because Limit as x approaches negative 2 f(x) does not exist.
Which statement describes whether the function is continuous at x = –2?
The function is continuous at x = –2 because f(–2) exists.
The function is continuous at x = –2 because Limit as x approaches negative 2 plus f(x) = f(–2).
The function is not continuous at x = –2 because Limit as x approaches negative 2 f(x) ≠ f(–2).
The function is not continuous at x = –2 because Limit as x approaches negative 2 f(x) does not exist.
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the answer i got is in the image below and i hope it helps
