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SVEN [57.7K]
3 years ago
5

Consider the function f (x) = StartLayout Enlarged left-brace first row negative StartFraction x + 5 Over x + 3 EndFraction, x l

ess-than negative 2 second row x cubed + 6, x greater-than-or-equal-to negative 2 EndLayout.
Which statement describes whether the function is continuous at x = –2?

The function is continuous at x = –2 because f(–2) exists.
The function is continuous at x = –2 because Limit as x approaches negative 2 plus f(x) = f(–2).
The function is not continuous at x = –2 because Limit as x approaches negative 2 f(x) ≠ f(–2).
The function is not continuous at x = –2 because Limit as x approaches negative 2 f(x) does not exist.

Mathematics
1 answer:
zalisa [80]3 years ago
8 0

Answer:

D

Step-by-step explanation:

Edge

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Given:
oksian1 [2.3K]

Answer:

9 units

Step-by-step explanation:

By the midsegment theorem,

AB=\dfrac{KN+LM}{2}

Since the ratio LM:KN=1:5, then LM=x,\ KN=5x and

18=\dfrac{x+5x}{2}\\ \\18=\dfrac{6x}{2}\\ \\18=3x\\ \\x=6\\ \\LM=6\ units\\ \\KN=30\ units

Draw two heights LE and MF. Quadrilateral ELMF is a rectangle, then EF = LM = 6 units.

Trapezoid KLMN is isosceles trapezoid (KL = MN), then KE = FN and

KE=FN=\dfrac{KN-EF}{2}=\dfrac{30-6}{2}=12\ units

Consider right triangle KLE. By the Pythagorean theorem,

KL^2=LE^2+KE^2\\ \\15^2=LE^2+12^2\\ \\LE^2=15^2-12^2\\ \\LE^2=225-144=81\\ \\LE=9\ units

3 0
3 years ago
If k represents a number then write an expression for the ratio of 3 less than k to 2 more than k
EleoNora [17]

The key words you should notice when looking at this word problem are “less than.” This means that the order is flipped, so “3 less than k” means “k minus 3.”

The expression for the ratio is k-3:k+3

Hope this helps

3 0
4 years ago
you took out a loan of $1,200 with the principal pay off of $200 a month each month you paid 200 plus the interest at a rate of
Bad White [126]
I think the answer you are looking for is $2,592
5 0
3 years ago
Which number line shows the solution to the inequality 5x + 3> - 17
Likurg_2 [28]
Xbdisksme. Dnsjwowke d me
7 0
3 years ago
The half-life of a radioactive kind of radium is 11 days. If you start with 72 grams of it, how
NISA [10]

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the concept of Radioactive decay.

N(t) = 72(1/2)^22/11

==> N(t) = 72 (1/2)^2

==> N(t) = 72/4

==> N(t) = 18 grams.

So the remaining would be 18 grams.

4 0
3 years ago
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