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rusak2 [61]
2 years ago
15

The masses of the oranges on sale at a farm stand are normally distributed with a mean of 239 grams and a standard deviation of

25
grams.
Enter the Z-score of an orange that has a mass of 259 grams.

Mathematics
1 answer:
ra1l [238]2 years ago
8 0

Answer:

0.8

Step-by-step explanation:

i just took the test

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sveticcg [70]

Answer:

Step-by-step explanation:

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3 years ago
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Carolyn has 9 quarters, 4 dimes, 7 nickels, and 2 pennies. Write and evaluate the expression to determine how much money she has
zlopas [31]

Answer:

3.02

Step-by-step explanation:

quarters are .25

dimes are .10

nickels are .05

pennies are .01

9 * .25 + 4 * .10 + 7 *.05 + 2 *.01

2.25+0.4+0.35+0.02

3.02

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3 years ago
PLZ HELP, GIVING BRAINLIEST!
mote1985 [20]

Answer:

  d)  (-3/2, -1/2)

Step-by-step explanation:

The midpoint (M) between two given points is the average of their coordinate values:

  M = (A + B)/2 = ((-8, 1) +(5, -2))/2 = (-3, -1)/2

  M = (-3/2, -1/2) . . . . . matches choice D

4 0
3 years ago
What’s the approximate value of tan 1
goldfiish [28.3K]

Answer: tan 1 radians = 1.557, tan 1 degrees = 0.017

6 0
2 years ago
Farmers often sell fruits and vegetables at farmers’ markets during the summer. Each tomato stand at the Bentonville farmers’ ma
olga nikolaevna [1]

Answer:

the probability that all tomatoes are sold is  0.919 (91.9%)

Step-by-step explanation:

since the random variable X= number of tomatoes that are demanded,  is normally distributed we can make the standard random variable Z such that:

Z=(X-μ)/σ = (83 - 125)/30 = -1.4

where μ= expected value of X= mean of X (since X is normally distributed)  , σ=standard deviation of X

then all tomatoes are sold if the demand surpasses 83 tomatos , therefore

P(X>83) = P(Z>-1.4) = 1- P(Z≤-1.4)

from tables of standard normal distribution →P(Z≤-1.4)=0.081 , therefore

P(X>83) = 1- P(Z≤-1.4)  = 1 - 0.081 = 0.919 (91.9%)

thus the probability that all tomatoes are sold is  0.919 (91.9%)

6 0
3 years ago
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