All categories

3 years ago

Solve for x 29=4x-11

Mathematics

2 answers:

Mnenie [13.5K]3 years ago

7 0

Answer:

The Right Answer is X=10

Gemiola [76]3 years ago

3 0

The correct answer for this would be X=10

You might be interested in

Who used less sugar 5/10 or 5/6

abruzzese [7]

It would be 5/6 because the denominator Is smaller than 10

can I be brainliest

7 0

4 years ago

Read 2 more answers

What is the y-intercept of the function, represented by the table of values

AleksandrR [38]

Answer:

Step-by-step explanation:

The table is given below

$\left|\begin{array}{c|cc}x&y\\--&--\\-2&15\\1&6\\2&3\\4&-3\\7&-12\end{array}\right|$

We can see that the table represents a linear function since by checking its slope.

Using:

Points (-2,15) and (1,6)
Points (1,6) and (2,3)

$Slope =\dfrac{6-15}{1-(-2)} =\dfrac{3-6}{2-1}=-3$

Therefore, the values represent a linear function.

A linear equation is of the form y=mx+b

Therefore:

y=-3x+b

Using the points (7,-12)

$-12=-3(7)+b\\-12=-21+b\\b=-12+21\\b=9$

Therefore, the y-intercept of the function, represented by the table of values is 9.

6 0

3 years ago

Which of the following fractions is equivalent to 5/6

expeople1 [14]

10/12, 15/18, 20/24, 25/30, 30/36, 35/42, 40/48, 45/54, 50/60, and so on ...
Source: Equivalent fractions for 5/6

4 0

3 years ago

Read 2 more answers

PLEASE ANSWER I WILL MARK AS BRAINLIEST

Tomtit [17]

Answer:

Six

Step-by-step explanation:

1.Convert all volumes to millilitres

(a) Chlorpheniramine

V = 100 mL

(b) Lidocaine

$V = \text{2 fl oz} \times \dfrac{\text{29.57 mL}}{\text{1 fl oz}} = \textbf{59 mL}$

(c) Banana flavouring

$V = \dfrac{1}{2}\text{ tsp} \times \dfrac{\text{4.928 mL}}{\text{1 tsp}} = \textbf{2.5 mL }$

2. Calculate the total volume

Chlorpheniramine = 100 mL

Lidocaine = 59

Banana flavouring = 2.5

TOTAL = 162 mL

3. Calculate the number of doses

$\text{Doses} = \text{162 mL} \times \dfrac{\text{1 dose}}{\text{10 mL}} = \text{16.2 doses}\\\\\text{You can't take a fraction of a dose, so the there are $\large \boxed{\textbf{16 doses}}$}$

5 0

3 years ago

The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x

RoseWind [281]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

Firstly we will calculate the general probability that of P(a < X < b)

P(a < X < b) = $\int_{a}^{b} \frac{2}{x^{3}} dx$ = $2\int_{a}^{b} x^{-3} dx$

= $2[ \frac{x^{-3+1} }{-3+1}]^{b}_a dx$ { Because $\int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a$ }

= $2[ \frac{x^{-2} }{-2}]^{b}_a$ = $\frac{2}{-2} [ x^{-2} ]^{b}_a$

= $-1 [ b^{-2} - a^{-2} ]$ = $\frac{1}{a^{2} } - \frac{1}{b^{2} }$

a) Now P(X < 5) = P(1 < X < 5) {because x > 1 }

Comparing with general probability we get,

P(1 < X < 5) = $\frac{1}{1^{2} } - \frac{1}{5^{2} }$ = $1 - \frac{1}{25}$ = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/ $8^{2}$ - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = $\frac{1}{6^{2} } - \frac{1}{10^{2} }$ = $\frac{1}{36} - \frac{1}{100 }$ = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

= $(\frac{1}{1^{2} } - \frac{1}{6^{2} })$ + (1/ $10^{2}$ - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

⇒ P(1 < X < x) = 0.75

⇒ $\frac{1}{1^{2} } - \frac{1}{x^{2} }$ = 0.75

⇒ $\frac{1} {x^{2} }$ = 1 - 0.75 = 0.25

⇒ $x^{2}$ = $\frac{1}{0.25}$ ⇒ $x^{2}$ = 4 ⇒ x = $2$

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0

3 years ago