Okay so we need to figure out the width of the swimming pool using the length, and we know the width is 10 ft shorter than twice the width. I believe the easiest way to do this would be to first do 35-10, and then divide it in half. That gives us 12.5. To check our work I'll do the problem 12.5+12.5+10=35.
The width of the swimming pool is 12.5 ft.
Answer:
<h3>6 degrees</h3>
Step-by-step explanation
Find the diagram attached. In Line geometry, there is a theorem that states that the sum of the adjacent interior angles is 180 degrees. According to the diagram, the adjacent interior angles are 7x- 15 and 24x + 9.
The sum of this angles must give 180 degrees as shown;
7x-15 + 24x + 9 = 180
7x+24x-15+9 = 180
31x-6 = 180
31x = 180+6
31x = 186
x = 186/31
x = 6
Hence the value of x is 6 degrees
The center is at origin O(0,0).
If it contains the point, P(-8,6), then the radius r is, by Pythagoras theorem,
r=sqrt((-8)^2+6^2)=10
The general equation of a circle at centre (xc,yc) with radius r is given by
(x-xc)^2+(y-yc)^2=r^2
Substituting r=10, (xc,yc)=(0,0)
the resulting equation is therefore
(x-0)^2+(y-0)^2=10^2
or simply
x^2+y^2=100
Answer:
AC = 12 units.
Step-by-step explanation:
Δ ACD is right-angled. ( as CD ⊥ AB).
cos 45° = CD / AC = 6√2 / AC
AC = 6√2 / cos 45°
AC = 6√2 / 1 /√2
= 6√2 *√2
= 6 * 2
= 12 (answer)
HOPE THIS HELPED ;3
No, it does not have a straight line. (A)
