All categories

3 years ago

What is one way during the G0 phase that a mistake during the cell cycle could result in problens for the G0 phase?

1 answer:

3 0

The G0 phase (G sub zero) or the zero of G is a period of the cell in which it remains in a vegetative state. The G0 phase is seen as a distinct and quiet stage that occurs outside the cell cycle. This phase is related to the "Post-Mitotic" state because they are in a non-dividing phase outside of the cell cycle; some cell types (such as neurons and heart muscle cells) when they reach maturity (that is, when they are terminally differentiated) become post-mitotic (enter the G0 phase), and perform their main functions for the rest of the life of the organism. Poly-nucleated muscle cells that do not undergo cytokinesis are often considered G0 phase cells.

You might be interested in

The planets show phases just like the moon does. Explain why we will never see a full Venus or full Mercury, even though we can

faltersainse [42]

Answer:

Because Venus and Mercury are closer to the sun they are never visible at around midnight

Explanation:

I've read about this in articles

6 0

3 years ago

When pink sweet peas were self-pollinated and the seeds were collected and sown, the following flower colors were obtained: Red

Pavlova-9 [17]

Answer:

c. 1:2:1

The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.

Explanation:

If flower color were determined by a gene showing incomplete dominance, the possible genotypes and phenotypes are as follows:

RR- red
ww - white
Rw - pink

If pink sweet peas are self-pollinated, then a cross between two heterozygous individuals is done (Rw x Rw).

From this cross the expected ratios are:

1/4 RR (red)
2/4 Rw (pink)
1/4 ww (white)

So the null hypothesis is that the observed results exhibit a 1:2:1 ratio.

<h3>Chi square test</h3>

$X^{2} = \sum \frac{(Observed - Expected)^2}{Expected}$

The observed frequencies were:

34 Red
76 Pink
40 White

Total 150

The expected frequencies for our null hypothesis are:

1/4 x 150 = 37.5 Red
2/4 x 150 = 75 Pink
1/4 x 150 = 37.5 white

$X^{2} = \frac{(34- 37.5)^2}{37.5} + \frac{(76- 75)^2}{75} + \frac{(40- 37.5)^2}{37.5}$

$X^2=0.5067$

The degrees of freedom (DF) are calculated as number of phenotypes - 1; in this case DF = 3-1 = 2.

If we look at the Chi square table, for 2 DF and a probability of p0.05, the critical value is 5.991

Our X^2 value of 0.5067 is less than the critical value, so we do not reject the null hypothesis. The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.

8 0

3 years ago

Explain biodiversity

koban [17]

The variety of all life forms on Earth.

6 0

3 years ago

In a unique species of plants, flowers may be yellow, blue, red, or mauve. All colors may be true-breeding. If plants with blue

Zolol [24]

Answer:

F1) 100% bbRr, red flowered plants.

Explanation:

Available data:

flowers may be yellow, blue, red, or mauve
colors may be true-breeding
the cross of blue-flowered plants with red-flowered plants, produce plants that have yellow flowers
F2 generation: 9/16 yellow, 3/16 blue, 3/16 red, and 1/16 mauve.

Knowing that the phenotypic ratio is 9:3:3:1, we can assume that there are two genes involved in the flower color expression. We can name these genes B and R with a dominant and a recessive allele each (B, b and R, r respectively).

According to the first cross, we might establish the following genotypes:

1st Cross: blue-flowered plant x red-flowered plant

Parentals) BBrr x bbRR

Gametes) Br, Br, Br, Br bR, bR, bR, bR

F1) 100% BbRr, yellow plants

Parentals) BbRr x BbRr

Gametes) BR, Br, bR, br

BR, Br, bR, br

Punnett square) BR Br bR br

BR BBRR BBRr BbRR BbRr

Br BBRr BBrr BbRr Bbrr

bR BbRR BbRr bbRR bbRr

br BbRr Bbrr bbRr bbrr

F2) 9/16 yellow ---> 1/16 BBRR + 2/16 BBRr + 4/16 BbRr + 2/16 BbRR

3/16 blue ------> 1/16 BBrr + 2/16 Bbrr

3/16 red---------> 1/16 bbRR + 2/16 bbRr

1/16 mauve ----> 1/16 bbrr

So,

Yellow-flowered plants: BBRR, BBRr, BbRR, BbRr
Red-flowered plants: bbRR, bbRr
Blue-flowered plants: BBrr, Bbrr
Mauve-flowered plants: bbrr

According to these genotypes, the second cross would be like following,

2nd Cross: true-breeding red-flowered plants with true-breeding mauve flowered plants.

Parentals) bbRR x bbrr

Phenotype) Red Mauve

Gametes) bR, bR, bR, bR br, br, br, br

Punnett square) bR bR bR bR

br bbRr bbRr bbRr bbRr

F1) 100% bbRr, red flowered plants.

6 0

3 years ago

Help taking it now worth 10 points

Karolina [17]

The Answer is the Intertidal Zone

3 0

3 years ago

Read 2 more answers

What is one way during the G0 phase that a mistake during the cell cycle could result in problens for the G0 phase?​

What is one way during the G0 phase that a mistake during the cell cycle could result in problens for the G0 phase?