I have done a and b but I am really struggling on C

The least common denominator of two fractions is 28. If you subtract the two denominators, their difference is 10. What are the

wel

14 and 28 are two different common denominators for the fractions and we convert both fractions to eighteenths we can subtract 3 eighteenths from 10

so what do you think the answer is
this is just a example

7 0

3 years ago

Travis takes out a loan from his bank for $3,500. At the end of the year, Travis will need to pay the loan back to his bank alon

Reil [10]

Answer:

$3,787

Step-by-step explanation:

frist find the amount of intrest

3,500 X 0.082 X 1 = 287

next add the oragial amount to the amount of intrest

3,500 + 287 = 3,787

6 0

2 years ago

Susie has a bag of marbles containing 3 Red, 7 Green, and 10 Blue marbles.

morpeh [17]

Answer:

1) a) 0.0945

b) 0.1062

2) a) 0.0138

b) 0.00081

3) a) 0.00094

b) 0.00083

4) 301.68 cents

5) 0.0056

Step-by-step explanation:

Since there are 3 Red, 7 Green, and 10 Blue marbles.

Total number of marbles N = 20

Probability (Red) = 3/20

Probability (Green) = 7/20

Probability (Blue) = 10/20

1) the probability of picking 5 marbles and getting at least one red marble

A) with replacement

P(at least 1 red of 5)= (3/20 * 17/20 * 17/20 * 17/20 * 17/20) + (3/20 * 3/20 * 17/20 * 17/20 * 17/20) + (3/20 * 3/20 * 3/20 * 17/20 * 17/20)

P(at least 1 red of 5) = 0.0783 +0.0138 + 0.0024 = 0.0945

B) without replacement

P(at least 1 red of 5) = ( 3/20 * 17/19* 16/18 * 15/17 * 14/16) + (3/20 * 2/19 * 17/18 * 16/17 * 15/16) + (3/20 * 2/19 * 1/18 * 17/17 * 16/16)

P(at least 1 red of 5) = 0.0921 + 0.01316 + 0.0009 = 0.1062

2) the probability of picking 6 marbles having 2 of each color

A) with replacement

P( 6, 2 of each) = 3/20 * 3/20 * 7/20 * 7/20 * 10/20 * 10/20

P( 6, 2 of each) = 0.0138

B) without replacement

P( 6, 2 of each) = 3/20 * 2/19 * 7/18 * 6/17 * 10/16 * 9/15

P( 6, 2 of each) = 0.00081

3) Pick 8 marbles: 4 green and 4 blue

A) with replacement

P(8, 4G and 4 B) = 7/20*7/20*7/20*7/20*10/20*10/20*10/20

P(8, 4G and 4 B) = 0.00094

B) without replacement

P(8, 4G and 4 B) = 7/20*6/19*5/18*4/17*10/16*9/15*8/14*7/13 = 0.00083

4) getting at least 6 marbles of the same color

Only Green and Blue marbles are more than 6

P(at least 6 marbles of the same color) = (7/20*6/19*5/18*4/17*3/16*2/15) + (10/20*9/19*8/18*7/17*6/16*5/15)

= 0.00018 + 0.00542

P(at least 6 marbles of the same color) = 0.0056

Cost of 6 .marbles= 6* 50 cents

C = 300 cents

Therefore, You will have to pay

(1 + 0.0056) 300 cent = 301.68 cents to be sure of getting at least 6 marbles of the same color

5) getting at least 6 marbles of the same color

Only Green and Blue marbles are more than 6

P(at least 6 marbles of the same color) = (7/20*6/19*5/18*4/17*3/16*2/15) + (10/20*9/19*8/18*7/17*6/16*5/15)

= 0.00018 + 0.00542

P(at least 6 marbles of the same color) = 0.0056

6 0

2 years ago

Which of the following pairs of numbers contains like fractions? A. 5⁄6 and 10⁄12 B. 3⁄2 and 2⁄3 C. 3 1⁄2 and 4 4⁄4 D. 6⁄7 and 1

ElenaW [278]

<h2>Hello!</h2>

The answers are:

A.

$\frac{5}{6}$ and $\frac{10}{12}$

D.

$\frac{6}{7}$ and $1\frac{5}{7}$

To find which of the following pairs of numbers contains like fractions, we must remember that like fractions are the fractions that share the same denominator.

We are given two fractions that are like fractions. Those fractions are:

Option A.

$\frac{5}{6}$ and $\frac{10}{12}$

We have that:

$\frac{10}{12}=\frac{5}{6}$

So, we have that the pairs of numbers

$\frac{5}{6}$

and

$\frac{5}{6}$

Share the same denominator, which is equal to 6, so, the pairs of numbers contains like fractions.

Option D.

$\frac{6}{7}$ and $1\frac{5}{7}$

We have that:

$1\frac{5}{7}=1+\frac{5}{7}=\frac{7+5}{7}=\frac{12}{7}$

So, we have that the pair of numbers

$\frac{6}{7}$

and

$\frac{12}{7}$

Share the same denominator, which is equal to 7, so, the pairs of numbers constains like fractions.

Also, we have that the other given options are not like fractions since both pairs of numbers do not share the same denominator.

The other options are:

$\frac{3}{2},\frac{2}{3}$

and

$3\frac{1}{2},4\frac{4}{4}$

We can see that both pairs of numbers do not share the same denominator so, they do not contain like fractions.

Hence, the answers are:

A.

$\frac{5}{6}$ and $\frac{10}{12}$

D.

$\frac{6}{7}$ and $1\frac{5}{7}$

Have a nice day!

3 0

3 years ago

Mattie uses the discriminant to determine the number of zeros the quadratic equation 0 = 3x2 – 7x + 4 has. Which best describes

vaieri [72.5K]

Answer: 2 real zeros

discriminant: b^2 - 4ac
a = 3, b = -7, and c = 4
so, (-7)^2 - 4(3)(4) = 1
Since the discriminant is positive, there are 2 real zeros, if the discriminant was negative there would be 2 complex zeros, and if the discriminant equaled 0 then there is one real answer

3 0

2 years ago

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