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dsp73
3 years ago
9

Expand and simply (x + 3) (x + 5)

Mathematics
1 answer:
kifflom [539]3 years ago
4 0
Here’s the answer :)

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If 75 is 25% of a value, what is that value?
sertanlavr [38]
75÷25%
25%=0.25
75÷0.25
=300
Your answer is 300
7 0
3 years ago
If xt = 3y -1 and us = 28, find the value of y
olga55 [171]
3y - 1 = 28
+ 1 + 1
----------------
3y = 29
---- ----
3 3
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8 0
3 years ago
What is the length of the hypotenuse of the triangle below?​
Vedmedyk [2.9K]

Answer:

Step-by-step explanation:

So here we have a 45-45-90 triangle.

This a special right triangle were the sides across from the 45 degree angles can be considered x, while the hypotenuse is two square roots of x.

Here since we have the sides across from the 45 degree angle we can conclude that x = 9\sqrt{2}

So if we wanted the hypotenuse we would just plug in this value of x like so:

hyp = x\sqrt{2} \\

hyp = (9\sqrt{2})(\sqrt{2})

hyp = 9(2)\\

hyp = 18

Therefore the hypotenuse is 18.

3 0
3 years ago
An object is launched straight up into
DiKsa [7]

Answer:

  t ∈ {1, 3}

Step-by-step explanation:

You want to find t such that ...

  h = 27

  27 = -8t^2 +32t +3 . . . . . . substitute the expression for h

  24 = -8t^2 +32t . . . . . . . . . subtract 3

  -3 = t^2 -4t . . . . . . . . . . . . . divide by -8

  1 = t^2 -4t +4 = (t -2)^2 . . . . add 4 to complete the square

  ±√1 = t -2 . . . . . . . . . . . . . . take the square root

  t = 2 ± 1 . . . . . . . . . . . . . . . . add 2

  t = 1 or 3

The object is 27 ft off the ground at t = 1 and again at t = 3.

8 0
3 years ago
Somebody please help me with this geometry work
dimulka [17.4K]

Answer:

m∠EGF = 65°  and m∠CGF = 115°

Step-by-step explanation:

Given;

∠EFG = 50°

EF = FG

Solution,

In ΔEFG m∠EFG = 50° and EF = FG.

Since triangle is an isosceles triangle hence their base angles are always equal.

∴m\angle FEG = m\angle EGF

Let the measure of ∠EGF  be x.

∴ m\angle FEG = m\angle EGF = x

Now by angle Sum property which states "The sum of all the angles of a triangle is 180°."

m∠EFG + m∠FEG + ∠EGF = 180

50\°+x+x=180\°\\50\°+2x=180\°\\2x= 180\°-50\°\\2x=130\°\\x=\frac{130}{2}= 65\°

Hence

m∠EGF = 65°  

Also 'The sum of angles that are formed on a straight line is equal to 180°."

m∠EGF + m∠CGF = 180°

65° + m∠CGF = 180°

m∠CGF = 180° - 65° = 115°

Hence m∠EGF = 65°  m∠CGF = 115°

8 0
3 years ago
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