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gizmo_the_mogwai [7]
3 years ago
11

Which statement describes the system of equations?

Mathematics
1 answer:
Masja [62]3 years ago
7 0

Answer:

1.) It has one solution (–5, 5).

if you click on the photo it will show you how to get the answer. I hope this helps you.

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Please answer as soon as possible. Use the graphing tool to graph this system of equations.​
yarga [219]

Answer:

Step-by-step explanation:

6 0
3 years ago
How do you change 5.5 into a fraction?
Scrat [10]
5.5 in fraction is 5 1/2 

hope that helps :)
4 0
3 years ago
Read 2 more answers
A model rocket is launched straight upward. The solid fuel propellant pushes the rocket off the ground at an initial velocity of
anastassius [24]

Answer:

a) 72.25sec

b) 6.25secs

c) after 10.5secs and 2 secs

Step-by-step explanation:

Given the height reached by the rocket expressed as;

s(t)= -4t^2 + 50t - 84

At maximum height, the velocity of the rocket is zero i.e ds/dt  = 0

ds/dt = -8t + 50

0 = -8t + 50

8t = 50

t = 50/8

t = 6.25secs

Hence it will reach the maximum height after 6.25secs

To get the maximum height, you will substitute t - 6.25s into the given expression

s(t)= -4t^2 + 50t - 84

s(6.25) = -4(6.25)^2 + 50(6.25) - 84

s(6.25) = -156.25 + 312.5 - 84

s(6.25)  = 72.25feet

Hence the maximum height reached by the rocket is 72.25feet

The rocket will reach the ground when s(t) = 0

Substitute into the expression

s(t)= -4t^2 + 50t - 84

0 = -4t^2 + 50t - 84

4t^2 - 50t + 84 = 0

2t^2 - 25t + 42 = 0

2t^2 - 4t - 21t + 42 = 0

2t(t-2)-21(t-2) = 0

(2t - 21) (t - 2) = 0

2t - 21 = 0 and t - 2 = 0

2t = 21 and t = 2

t = 10.5 and 2

Hence the time the rocket will reach the ground are after 10.5secs and 2 secs

3 0
3 years ago
I will brainlist who can answer this 2 question!
LUCKY_DIMON [66]
Where’s the question?
3 0
2 years ago
PLEASE HELPPP MEEEEEE
Allushta [10]
Answer: T-birds and bulldogs

Explanation:

T-bird has 15 win and 5 lose so the ratio is 15/5 = 3

Bulldogs has 12 win and 4 lose so the ratio is 12/4 = 3

Therefore, their ratio are equivalent
6 0
3 years ago
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