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Setler79 [48]
3 years ago
13

SOMEONE. PLS HELP I ASKED A QUESTION AND I'LL GIVE BRAINLIEST JUST PLS ANSWER IT

Mathematics
2 answers:
kkurt [141]3 years ago
6 0

Dora

Boots

Come on, Dora

Do-do-do-do-Dora (alright)

Do-do-do-do-Dora

Do-do-do-do-Dora

Do-do-do-do-Dora (let's go)

Dora, Dora, Dora the explorer (Dora!)

Boots and super cool Exploradora

Need your help

Grab your backpack, let's go

Jump in, ¡vámonos!

You can lead the way

Hey! Hey!

Do-d-Dora

Do-d-Dora

Do-d-Dora

Do-d-Dora

Swiper no swiping

Swiper no swiping

(Oh, man)

Dora the explorer!

Thepotemich [5.8K]3 years ago
3 0

Answer:

Ok, I'll try

Step-by-step explanation:

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-x+2y=9<br> -7x-2y=-1 <br> Solve each system by elimination
g100num [7]
X - 2y = - 9
7x + 2y = 1

x - 2y = - 9
(+)
7x + 2y = 1
___________
8x = - 8

x = - 1

- 1 - 2y = - 9
2y = 8
y = 4

i am a mathematics teacher. if anything to ask please pm me
5 0
3 years ago
If y=2x-8, what is the value of x when y=0?<br><br> A)-4<br><br> B)0<br><br> C)4<br><br> D)8
Savatey [412]
If y=0 then,
2x-8=0
2x=8
X=8/2
X=4
Answer is c
6 0
3 years ago
Read 2 more answers
Analyze the expression and then choose the sentences describing whether the binomial theorem can be used to factor it. Check all
daser333 [38]

Answer:

Step-by-step explanation:

N is 3 bc #of terms minus 1

Exponents go from 3>2>x>none

Can be factored using binomial theorem

8 0
3 years ago
Read 2 more answers
What is the length of RS.
Natali [406]

Consider, in ΔRPQ,

RP = R (Radius of larger circle)

PQ = r (radius of smaller circle)

We have to find, RQ, by Pythagoras theorem,

RP² = PQ²+RQ²

R² = r²+RQ²

RQ² = R²-r²

RQ = √(R²-r²

Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ

RS = 2√(R²-r²)

5 0
3 years ago
If ABCD is congrunent to , pqrs, then AD is congrent to ?
katovenus [111]

Answer:

AD is congruent to RS

Step-by-step explanation:

we know that

If two figures are congruent, then its corresponding sides and its corresponding angles are congruent

In this problem

If

ABCD≅PQRS

then

<em>Corresponding angles</em>

∠A≅∠P

∠B≅∠Q

∠C≅∠R

∠D≅∠S

<em>Corresponding sides</em>

AB≅PQ

BC≅QR

CD≅RS

AD≅PS

7 0
3 years ago
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