3 years ago

Solve each system by graphing

Mathematics

1 answer:

Ne4ueva [31]3 years ago

5 0

2,-4 is you awnser. good day to you

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Decide whether quadrilateral ABCD with vertices 4(3,1), B(-1,-1) C(1,3), and D(5.5) is a rectangle, rhombus,square, or parallelo

Sergeeva-Olga [200]

Answer: rhombus

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By inspection, we can tell that there are no right angles, so we can determine it is not a square or a rectangle.

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$AB=\sqrt{(-1-3)^{2}+(-1-1)^{2}}=\sqrt{16+4}=2\sqrt{5}\\BC=\sqrt{(-1-1)^{2}+(-1-3)^{2}}=\sqrt{4+16}=2\sqrt{5}$

As AB=BC, there is indeed a pair of consecutive congruent sides, and thus the most specific classification is a <em>rhombus</em>

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