Answer:
0.1333 = 13.33% probability that bridge B was used.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Arrives home by 6 pm
Event B: Bridge B used.
Probability of arriving home by 6 pm:
75% of 1/3(Bridge A)
60% of 1/6(Bridge B)
80% of 1/2(Bridge C)
So

Probability of arriving home by 6 pm using Bridge B:
60% of 1/6. So

Find the probability that bridge B was used.

0.1333 = 13.33% probability that bridge B was used.
well, do a payments table of values, just like before for each mont hmm let's see
1st month.......................3500 + p(1)
2nd month....................3500 + p(2)
3rd month.....................3500 + p(3)
4th month.....................3500 + p(4)
5th month.....................3500 + p(5)
36th month..................3500 + p(36)

Answer:
4 4/2
Step-by-step explanation:
What you do is you have to do 8-4=4 5-1=4 6-4=2 so there for the answer is 4 4/2
If you factor the trinomial using the AC method the answer would be
(x-3)(x+9)
C.
y - 65 = -10(x - 6)
is what i say it is but im not for sure, so sry if im wrong.