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Vika [28.1K]
2 years ago
9

Solve x2 – 18x + 81 = 4 by completing the square. Select any solutions that apply.

Mathematics
1 answer:
Masteriza [31]2 years ago
3 0

Answer:

7 and 11

Step-by-step explanation:

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HELPPP ASAP PLEASEEE THANK YOU
ahrayia [7]

Step 1: Find the slope

Slope formula = (y2 - y1) / (x2 - x1)

---You can choose any two points when finding the slope!

Point 1 = (-2,-10)

Point 2 = (-1,-3)

Slope = (-3 - - 10) / (-1 - - 2)

Slope = 7 / 1

Slope = 7

Step 2: Find the y-intercept

Now that we have the slope, we'll plug that and one point into slope-intercept form. Then, we'll solve for b.

Slope-Intercept Form: y = mx + b

---m is the slope, b is the y-intercept

Point = (-1, -3)

Slope = 7

-3 = 7(-1) + b

-3 = -7 + b

b = 4

Step 3: Put it all together

Now that we know the slope and y-intercept, all that's left to do is plug them into slope-intercept form.

Slope-Intercept Form: y = mx + b

Slope = 7

Y-Intercept = 4

Line: y = 7x + 4

Correct Answer: A

Hope this helps!

5 0
2 years ago
PLZ HELP BRAINLIEST AND 20 POINTS
iris [78.8K]

Answer:

the last set

Step-by-step explanation:

hope this helps :) have a nice day !!

**please let me know if this was wrong**

7 0
3 years ago
Suppose you toss a fair coin 10 times, let X denote the number of heads. (a) What is the probability that X=5? (b) What is the p
zubka84 [21]

Answer:  The required answers are

(a) 0.25,    (b) 0.62,    (c) 6.

Step-by-step explanation:  Given that we toss a fair coin 10 times and X denote the number of heads.

We are to find

(a) the probability that X=5

(b) the probability that X greater or equal than 5

(c) the minimum value of a such that P(X ≤ a) > 0.8.

We know that the probability of getting r heads out of n tosses in a toss of coin is given by the formula of binomial distribution as follows :

P(X=r)=^nC_r\left(\dfrac{1}{2}\right)^r\left(\dfrac{1}{2}\right)^{n-r}.

(a) The probability of getting 5 heads is given by

P(X=5)\\\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}\\\\\\=\dfrac{10!}{5!(10-5)!}\dfrac{1}{2^{10}}\\\\\\=0.24609\\\\\sim0.25.

(b) The probability of getting 5 or more than 5 heads is

P(X\geq 5)\\\\=P(X=5)+P(X=6)+P(X=7)+P(X=8)+P(X=9)+P(X=10)\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}+^{10}C_6\left(\dfrac{1}{2}\right)^6\left(\dfrac{1}{2}\right)^{10-6}+^{10}C_7\left(\dfrac{1}{2}\right)^7\left(\dfrac{1}{2}\right)^{10-7}+^{10}C_8\left(\dfrac{1}{2}\right)^8\left(\dfrac{1}{2}\right)^{10-8}+^{10}C_9\left(\dfrac{1}{2}\right)^9\left(\dfrac{1}{2}\right)^{10-9}+^{10}C_{10}\left(\dfrac{1}{2}\right)^{10}\left(\dfrac{1}{2}\right)^{10-10}\\\\\\=0.24609+0.20507+0.11718+0.04394+0.0097+0.00097\\\\=0.62295\\\\\sim 0.62.

(c) Proceeding as in parts (a) and (b), we see that

if a = 10, then

P(X\leq 0)=0.00097,\\\\P(X\leq 1)=0.01067,\\\\P(X\leq 2)=0.05461,\\\\P(X\leq 3)=0.17179,\\\\P(X\leq 4)=0.37686,\\\\P(X\leq 5)=0.62295,\\\\P(X\leq 6)=0.82802.

Therefore, the minimum value of a is 6.

Hence, all the questions are answered.

3 0
3 years ago
The supplementary angle of π/5 is
bija089 [108]
The supplementary angle is 0.628. Hope that helps
3 0
3 years ago
3.006 rounded to the nearest tenth
Ann [662]
3.006 rounded to the nearest tenth is 3.0. This is due to the fact that the 6 rounded up will mean that the current 0 becomes 1, but this will not be carried to the tenth when rounding up.
3 0
3 years ago
Read 2 more answers
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