ANSWER
C) Triangle
EXPLANATION
Solving a triangle is the process of calculating unknown side lengths or angle measures of a triangle if certain of the side lengths and/or angle measures are known.
We use the sine rule and cosine rule to find the missing sides and angles.
If the triangle has a right angle, then this is a special case, where we can use the trigonometric ratios and the Pythagoras theorem to find the unknown angles and sides.
Answer:
f(x) = -19/9(x + 3)² + 5
Step-by-step explanation:
Given the vertex, (-3, 5) and the point, (0, 14):
Use the following quadratic equation formula in vertex form:
f(x) = a(x - h)² + k
where:
(h, k) = vertex
a = determines whether the graph opens up or down, and makes the graph wide or narrow.
<em>h</em><em> </em>= determines how far left or right the parent function is translated.
<em>k</em> = determines how far up or down the parent function is translated.
Plug in the values of the vertex, (-3, 5) and the given point, (0, 14) to solve for <em>a</em>:
f(x) = a(x - h)² + k
14 = a(0 + 3)² + 5
14 = a(3)² + 5
14 = a(9) + 5
Subtract 5 from both sides:
-14 - 5 = 9a
-19 = 9a
Divide both sides by 9 to solve for a:
-19/9 = 9a/9
-19/9 = a
Therefore, the quadratic function in vertex form is:
f(x) = -19/9(x + 3)² + 5
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The intercepts of the given equations is as given in the task content is; Choice B; (15,0,0),(0,10,0) ,(0,0,5).
<h3>What are the intercepts of the equation as give in the task content?</h3>
The x-intercept of the given equation can be determined by setting values of y and z to zero.
The y-intercept can be determined by setting x and z to zero.
While the z-intercept can be determined by setting x and y to zero.
Consequently, the X-intercept of the given equations is; 2x +3(0) = 30; x = 15.
Therefore, we have; (15,0,0)
The y-intercept is therefore; 2(0) +3y = 30; 3y = 30; y = 30/3 = 10 and. we have; (0,15,0)
And hence, the z-intercept is; z = 30/6 = 5.
Read more on intercept;
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Answer: 1: B
Step-by-step explanation:
5+5=10
15-5=10
5x2=10
20/2=10
10^1 (10 to the power of 1) or 0.1^-1 (0.1 to the power of -1)
