Let the value of the car be represented by V and the amount of years by y.
This gives us the following formula:
V = 25,635 - 3000y
(This is because we start with a value of $25,635 and the value decreases by $3,000 every year 'y')
Now, we want to know when the car is worth $3,135, so we know V = 3,135
Now we can make up our equation:
25,365 - 3,000y = 3,135
Collecting terms gives us:
-3,000y = -22,500
Finally we divide by -3,000 to find 'y'
y = -22,500 / -3,000 = 7.5
Hence, the car will be worth $3,135 after 7.5 years.
Answer:
not completely sure but I think it's it's 13.4
Four, -6 in terms of standard unit factors I NJ makes no sense
To solve this we are going to use the future value of annuity ordinary formula:
![FV=P[ \frac{(1+ \frac{r}{n} )^{kt} -1}{ \frac{r}{n} } ]](https://tex.z-dn.net/?f=FV%3DP%5B%20%5Cfrac%7B%281%2B%20%5Cfrac%7Br%7D%7Bn%7D%20%29%5E%7Bkt%7D%20-1%7D%7B%20%5Cfrac%7Br%7D%7Bn%7D%20%7D%20%5D)
where

is the future value

is the periodic payment

is the interest rate in decimal form

is the number of times the interest is compounded per year

is the number of payments per year

is the number of years
We know for our problem that

and

. To convert the interest rate to decimal form, we are going to divide the rate by 100%:

Since the deposit is made semiannually, it is made 2 times per year, so

.
Since the type of the annuity is ordinary, payments are made at the end of each period, and we know that we have 2 periods, so

.
Lets replace the values in our formula:
![FV=P[ \frac{(1+ \frac{r}{n} )^{kt} -1}{ \frac{r}{n} } ]](https://tex.z-dn.net/?f=FV%3DP%5B%20%5Cfrac%7B%281%2B%20%5Cfrac%7Br%7D%7Bn%7D%20%29%5E%7Bkt%7D%20-1%7D%7B%20%5Cfrac%7Br%7D%7Bn%7D%20%7D%20%5D)
![FV=6200[ \frac{(1+ \frac{0.06}{2} )^{(2)(5)} -1}{ \frac{0.06}{2} } ]](https://tex.z-dn.net/?f=FV%3D6200%5B%20%5Cfrac%7B%281%2B%20%5Cfrac%7B0.06%7D%7B2%7D%20%29%5E%7B%282%29%285%29%7D%20-1%7D%7B%20%5Cfrac%7B0.06%7D%7B2%7D%20%7D%20%5D)
We can conclude that the correct answer is <span>
$71,076.06</span>
Answer:
3 2/3
Step-by-step explanation:
Divide 11 by 3 using long division method. then place the quotient as whole number and reminder as numerator and dividend as denominator